INVCNT - Inversion Count
Let A[0 ... n - 1] be an array of n distinct positive integers. If i < j and A[i] > A[j] then the pair (i, j) is called an inversion of A. Given n and an array A your task is to find the number of inversions of A.
Input
The first line contains t, the number of testcases followed by a blank space. Each of the t tests start with a number n (n ≤ 200000). Then n + 1 lines follow. In the ith line a number A[i - 1] is given (A[i - 1] ≤ 107). The (n + 1)th line is a blank space.
Output
For every test output one line giving the number of inversions of A.
Example
Input: 2 3 3 1 2 5 2 3 8 6 1 Output: 2 5
hide comments
[Lakshman]:
2014-11-12 12:19:45
@Abi you have declared count as long long and your mergesort is returning int , So declare mergesort and merge long long instead. Hope this helps. Last edit: 2014-11-12 12:25:19 |
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Abi:
2014-11-12 06:59:38
I dont know ....why iam getting WA :(
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surayans tiwari(http://bit.ly/1EPzcpv):
2014-11-08 12:29:10
acce using merge ,, got acc using fast i/o with bit Last edit: 2014-11-08 12:44:38 |
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Vikas:
2014-10-12 15:39:58
I am getting WA even after checking my code many times.Please help.
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vikax:
2014-09-25 13:49:41
3 RTE coz of a silly mistake...... finally ac |
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Siya:
2014-09-23 12:49:05
AC in first chance :) |
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saumya:
2014-09-14 14:09:45
same as http://www.spoj.com/problems/CODESPTB/
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Gaurav Ahirwar:
2014-08-30 13:29:12
0.70 secs AC! :D |
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ankur manchanda:
2014-07-22 10:18:51
declare variable count as long long int.
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Anmol Pandey:
2014-07-18 17:30:53
Take array size 10^7+1 to remove SIGSEGV error |
Added by: | Paranoid Android |
Date: | 2010-03-06 |
Time limit: | 3.599s |
Source limit: | 50000B |
Memory limit: | 1536MB |
Cluster: | Cube (Intel G860) |
Languages: | All except: PERL6 |