INVCNT - Inversion Count
Let A[0 ... n - 1] be an array of n distinct positive integers. If i < j and A[i] > A[j] then the pair (i, j) is called an inversion of A. Given n and an array A your task is to find the number of inversions of A.
Input
The first line contains t, the number of testcases followed by a blank space. Each of the t tests start with a number n (n ≤ 200000). Then n + 1 lines follow. In the ith line a number A[i - 1] is given (A[i - 1] ≤ 107). The (n + 1)th line is a blank space.
Output
For every test output one line giving the number of inversions of A.
Example
Input: 2 3 3 1 2 5 2 3 8 6 1 Output: 2 5
hide comments
r0bo_dart:
2015-06-13 13:35:15
HINT: Dont use vector for this problem with your custom designed insert. That will slow things out. Use array instead. Cost me 4 TLEs... phew. Else Merge Sort works nice. and yeah the long long thingy too. |
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rudra21:
2015-06-13 00:28:26
variation of Merge Sort algo.
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ruler:
2015-06-11 11:19:44
thanks @cr |
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satyajit tourani:
2015-06-11 08:18:34
easy after reading theory from CLRS( mergesort ) :) AC in 0.27 seconds. :D |
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Akash Goel:
2015-06-10 21:13:39
Couldn't AC without long long. Dunno why |
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Nitesh Tiwari:
2015-06-05 11:14:02
Reading these comments does help a lot.
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Praveen Kulkarni:
2015-06-03 15:59:39
my 50th |
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hrwang_xn:
2015-06-01 17:37:57
use BIT. |
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scyth3r:
2015-05-27 14:21:16
@I W G T J have you considered blank lines as input? |
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I W G T J:
2015-05-27 09:59:18
Why WA? <snip>
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Added by: | Paranoid Android |
Date: | 2010-03-06 |
Time limit: | 3.599s |
Source limit: | 50000B |
Memory limit: | 1536MB |
Cluster: | Cube (Intel G860) |
Languages: | All except: PERL6 |