INVCNT - Inversion Count


Let A[0 ... n - 1] be an array of n distinct positive integers. If i < j and A[i] > A[j] then the pair (i, j) is called an inversion of A. Given n and an array A your task is to find the number of inversions of A.

Input

The first line contains t, the number of testcases followed by a blank space. Each of the t tests start with a number n (n ≤ 200000). Then n + 1 lines follow. In the ith line a number A[i - 1] is given (A[i - 1] ≤ 107). The (n + 1)th line is a blank space.

Output

For every test output one line giving the number of inversions of A.

Example

Input:
2

3
3
1
2

5
2
3
8
6
1


Output:
2
5

hide comments
i_am_looser: 2015-05-18 14:48:01

Done it using segment tree....

:.Mohib.:: 2015-05-17 08:08:19

Binary tree ==> AC :)

Prismatic: 2015-05-14 18:14:45

Easy using BIT

Cr: 2015-05-07 14:54:24

don't forget result is long long type

Phong: 2015-04-23 08:59:30

Why is my code getting WA? I tried to submit it on vn.spoj.com with a similar problem and the exact code and it got AC. Confused!!

Tony T.: 2015-04-15 07:07:57

Wrote something quick to generate test cases: <snip>

Last edit: 2022-06-26 16:04:52
Tony T.: 2015-04-14 06:54:06

I had a pointer problem, else merge sort works great.
Was just getting into BIT.. thought it was pretty complicated.

Last edit: 2015-04-15 07:08:46
Madhav: 2015-04-01 19:39:38

nope

Last edit: 2015-04-02 03:06:11
abvj: 2015-03-27 02:09:15

nope

Last edit: 2015-04-02 03:06:26
soshika: 2015-03-23 00:43:53

cool :B


Added by:Paranoid Android
Date:2010-03-06
Time limit:3.599s
Source limit:50000B
Memory limit:1536MB
Cluster: Cube (Intel G860)
Languages:All except: PERL6