BOTTOM - The Bottom of a Graph
We will use the following (standard) definitions from graph theory. Let V be a nonempty and finite set, its elements being called vertices (or nodes). Let E be a subset of the Cartesian product V×V, its elements being called edges. Then G=(V,E) is called a directed graph.
Let n be a positive integer, and let p=(e1,…,en) be a sequence of length n of edges ei∈E such that ei=(vi,vi+1) for a sequence of vertices (v1,…,vn+1). Then p is called a path from vertex v1 to vertex vn+1 in G and we say that vn+1 is reachable from v1, writing (v1→vn+1).
Here are some new definitions. A node v in a graph G=(V,E) is called a sink, if for every node w in G that is reachable from v, v is also reachable from w. The bottom of a graph is the subset of all nodes that are sinks, i.e., bottom(G)={v∈V∣∀w∈V:(v→w)⇒(w→v)}. You have to calculate the bottom of certain graphs.
Input Specification
The input contains several test cases, each of which corresponds to a directed graph G. Each test case starts with an integer number v, denoting the number of vertices of G=(V,E), where the vertices will be identified by the integer numbers in the set V={1,…,v}. You may assume that 1≤v≤5000. That is followed by a non-negative integer e and, thereafter, e pairs of vertex identifiers v1,w1,…,ve,we with the meaning that (vi,wi)∈E. There are no edges other than specified by these pairs. The last test case is followed by a zero.
Output Specification
For each test case output the bottom of the specified graph on a single line. To this end, print the numbers of all nodes that are sinks in sorted order separated by a single space character. If the bottom is empty, print an empty line.
Sample Input
3 3 1 3 2 3 3 1 2 1 1 2 0
Sample Output
1 3 2
hide comments
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badry atef:
2015-08-05 15:26:40
a very nice SCC problem :) |
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Medo:
2015-08-05 13:19:05
It's impossible for a graph to have no sink nodes. Don't account for that case if you are getting a WA. |
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Ankit Kumar:
2015-07-16 21:07:13
O(V+E) solution -> AC
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i_am_looser:
2015-06-06 21:27:19
Good question..... learnt something useful |
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Arafat dad Khan:
2015-06-03 17:57:47
Great problem for learning new things |
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Arya08:
2015-05-29 20:39:00
best dfs problem. solved by me(till now ) |
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ehacker:
2015-05-26 22:53:03
My testcases are correct even the ones which are mentioned in the comments, don't know, i am using a do while loop and output the value as i calculated for that case????
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eli:
2015-03-11 16:18:36
2 can't reach 1 so it works. |
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Archit Jain:
2014-12-26 20:13:55
seems easy but difficult to implement |
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|RAMSDEN|:
2014-12-25 21:09:22
A silly mistake costed me many WAs :p |
Added by: | Wanderley Guimarăes |
Date: | 2007-09-21 |
Time limit: | 1s |
Source limit: | 50000B |
Memory limit: | 1536MB |
Cluster: | Cube (Intel G860) |
Languages: | All except: ERL JS-RHINO |
Resource: | University of Ulm Local Contest 2003 |