LCA - Lowest Common Ancestor

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A tree is an undirected graph in which any two vertices are connected by exactly one simple path. In other words, any connected graph without cycles is a tree. - Wikipedia 

The lowest common ancestor (LCA) is a concept in graph theory and computer science. Let T be a rooted tree with N nodes. The lowest common ancestor is defined between two nodes v and w as the lowest node in T that has both v and w as descendants (where we allow a node to be a descendant of itself). - Wikipedia

Your task in this problem is to find the LCA of any two given nodes v and w in a given tree T.

For example the LCA of nodes 9 and 12 in this tree is the node number 3.

Input

The first line of input will be the number of test cases. Each test case will start with a number N the number of nodes in the tree, 1 <= N <= 1,000. Nodes are numbered from 1 to N. The next N lines each one will start with a number M the number of child nodes of the Nth node, 0 <= M <= 999 followed by M numbers the child nodes of the Nth node. The next line will be a number Q the number of queries you have to answer for the given tree T, 1 <= Q <= 1000. The next Q lines each one will have two number v and w in which you have to find the LCA of v and w in T, 1 <= v, w <= 1,000.

Input will guarantee that there is only one root and no cycles.

Output

For each test case print Q + 1 lines, The first line will have “Case C:” without quotes where C is the case number starting with 1. The next Q lines should be the LCA of the given v and w respectively.

Example

Input:
1
7
3 2 3 4
0
3 5 6 7
0
0
0
0
2
5 7
2 7

Output:
Case 1:
3
1

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$!:D: 2015-01-19 05:17:43

getting tle plzz help in testcase 0 only!!
my soln. is O(Q*(log(N)*N)
soln. id: 9408229

ideone link: <snip>

Last edit: 2022-09-10 23:24:42
raunakrocks: 2015-01-19 05:17:43

AC!!...nyce problem

Last edit: 2013-06-08 21:45:39
Haijun Deng: 2015-01-19 05:17:43

Please consider the following cases for WAs:
Input:
1
7
3 2 3 4
0
3 5 6 7
0
0
0
0
2
3 6
1 7

(Tjandra Satria Gunawan)(曾毅昆): 2015-01-19 05:17:43

@Noszály Csaba: Thanks for the info :-)

Noszály Csaba: 2015-01-19 05:17:43

@Tjandra: O(N) precomp + O(log(N)) per query? There are O(1) per query methods too.

(Tjandra Satria Gunawan)(曾毅昆): 2015-01-19 05:17:43

my bruteforce O(k*Q*N) without any precomputation is accepted with fast I/O and bitwise optimization ;-) still curious for better complexity...

Hussain Kara Fallah: 2015-01-19 05:17:43

Weak testcases , wrong solutions takes AC !!


Added by:hossamyosef
Date:2013-05-13
Time limit:0.600s-1.113s
Source limit:50000B
Memory limit:1536MB
Cluster: Cube (Intel G860)
Languages:All
Resource:FCIS/ASU Local Contest 2013