LASTDIG - The last digit
Nestor was doing the work of his math class about three days but he is tired of make operations a lot and he should deliver his task tomorrow. His math’s teacher gives him two numbers a and b. The problem consist of finding the last digit of the potency of base a and index b. Help Nestor with his problem. You are given two integer numbers: the base a (0 <= a <= 20) and the index b (0 <= b <= 2,147,483,000), a and b both are not 0. You have to find the last digit of ab.
Input
The first line of input contains an integer t, the number of test cases (t <= 30). t test cases follow. For each test case will appear a and b separated by space.
Output
For each test case output an integer per line representing the result.
Example
Input: 2 3 10 6 2
Output: 9 6
hide comments
ghazikhan13:
2019-07-17 13:17:46
hey guys, can anyone tell me why everyone did modules division by 10 only, why not any other number ??
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scolar_fuad:
2019-07-09 05:46:21
Just think like Big_Mod algorithm i or find pattern you will get answer
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sanket17:
2019-07-08 11:05:21
For all those who are getting WA after considering a=0,b=0 case also its due to pow() function here input is non_primitive so we cant use pow function it will not return the required value
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arphox:
2019-07-07 17:07:55
Hint: This can be done in O(1) time, just look for patterns in last digits, they will repeat somehow, somewhere :-) |
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imambungo:
2019-07-04 17:19:34
thanks sahruz_riyad |
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vurise18:
2019-06-27 11:09:29
what data type do we need to store b ? |
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ankyy_0103:
2019-06-22 13:40:05
My java Solution is not fitting in source code size . <(^_^)> |
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nagrahari:
2019-06-19 10:52:12
nice question |
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selfcoder24:
2019-06-12 09:31:04
use modular exponentiation with mod being 10 to fetch last digit. |
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kocko:
2019-06-09 18:53:09
Quite stupid requirement for the source code size.... |
Added by: | Jose Daniel Rodriguez Morales |
Date: | 2008-12-01 |
Time limit: | 1s |
Source limit: | 700B |
Memory limit: | 1536MB |
Cluster: | Cube (Intel G860) |
Languages: | All except: GOSU |
Resource: | Own |