INVCNT - Inversion Count


Let A[0 ... n - 1] be an array of n distinct positive integers. If i < j and A[i] > A[j] then the pair (i, j) is called an inversion of A. Given n and an array A your task is to find the number of inversions of A.

Input

The first line contains t, the number of testcases followed by a blank space. Each of the t tests start with a number n (n ≤ 200000). Then n + 1 lines follow. In the ith line a number A[i - 1] is given (A[i - 1] ≤ 107). The (n + 1)th line is a blank space.

Output

For every test output one line giving the number of inversions of A.

Example

Input:
2

3
3
1
2

5
2
3
8
6
1


Output:
2
5

hide comments
yaseenmollik: 2018-12-10 23:16:10

Used merge sort..Be careful to use long type instead of integer for count variable. Got wrong answer just for this mistake..

manuparmar35: 2018-11-14 19:33:58

Fenwick Tree :: AC in one go :)

r15habhgup11: 2018-10-30 11:05:02

solved using fenwick tree. ac in one go :)

eng_hardik: 2018-10-28 20:15:46

Use long in JAVA for storing the inversion-count to avoid WA

salman3007: 2018-10-10 16:22:44

beautiful use of merge_sort

kishan75: 2018-10-10 07:52:45

can anyone tell me constraints of test case T

yash0530: 2018-08-13 12:57:57

Use long to count inversions i got WA for using int in C++

divyansh_soni: 2018-08-12 15:42:54

AC in first go by Using BIT.

Last edit: 2018-08-12 15:43:23
ayusofayush: 2018-08-09 21:45:22

an application of merge sort.... ;)

caffeines: 2018-07-30 22:58:00

Policy-based data structures and AC


Added by:Paranoid Android
Date:2010-03-06
Time limit:3.599s
Source limit:50000B
Memory limit:1536MB
Cluster: Cube (Intel G860)
Languages:All except: PERL6