INVCNT - Inversion Count


Let A[0 ... n - 1] be an array of n distinct positive integers. If i < j and A[i] > A[j] then the pair (i, j) is called an inversion of A. Given n and an array A your task is to find the number of inversions of A.

Input

The first line contains t, the number of testcases followed by a blank space. Each of the t tests start with a number n (n ≤ 200000). Then n + 1 lines follow. In the ith line a number A[i - 1] is given (A[i - 1] ≤ 107). The (n + 1)th line is a blank space.

Output

For every test output one line giving the number of inversions of A.

Example

Input:
2

3
3
1
2

5
2
3
8
6
1


Output:
2
5

hide comments
anmoldua: 2017-09-14 20:44:47

fenwick tree easy

taksh: 2017-09-08 14:19:01

How to you solve this? Someone please send solution code for this. Been trying for the last 3 days.

polkerty: 2017-09-05 04:13:19

So my solution is really weird (respect to everyone who saw the merge sort). Basically I used 3 vectors and some carefully chosen constants to get the answer by sorting progressively smaller pieces of the array, and then using a bunch of binary searches to find the values I wanted.

jayharsh: 2017-08-25 16:36:54

Merge sort implementation in a innovative way.............

diaaeddin: 2017-08-21 13:00:29

AC in one go using trie

jarvis_1997: 2017-07-30 17:01:52

Comments are like GOT spoilers. Never look at them unless you are done ;)

studyfather: 2017-07-24 13:50:35

use merge sort and AC!!!

ani_geek9654: 2017-07-01 13:37:46

AC in 1
Just MergeSort

hzshang: 2017-06-30 18:26:07

Binary tree, easy :P

kartiks22: 2017-06-26 09:40:03

took me 2 hours to figure out long long mistake !!!


Added by:Paranoid Android
Date:2010-03-06
Time limit:3.599s
Source limit:50000B
Memory limit:1536MB
Cluster: Cube (Intel G860)
Languages:All except: PERL6