IDC1948 - Identity crisis
For every given number n we define x(n) as distance from n to the first number after n in form of 99...99. For example x(100)=899, x(45)=54, etc. Given several n numbers you have to find the Zp, where x(n) ≡ n (mod p).
Input
First line of input contains one number T (T < 20) - the number of test cases. In each of the next T lines contains one number each to represent n (0 < n < 30000000).
Output
In each line you have to write one number - the least p > 1 that x(n) ≡ n (mod p). If there is no such p the line should contain -1.
Example
Input: 2 234 5 Output: 3 -1
Explanation
x(234)=765. 765 mod 3=0, 234 mod 3=0 => 765 ≡ 234 (mod 3)
hide comments
Mitch Schwartz:
2014-02-07 16:19:31
@Mehmet Inal: I don't know if this is a spoiler (I'm trying to be vague), but you should be able to reduce the problem to something you know a lot about. :) |
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mehmetin:
2014-02-07 14:45:11
Is there an O(1) solution for this? |
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Mostafa 36a2:
2014-02-07 13:29:22
Ha ha ! the worst solution :D
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Mostafa 36a2:
2014-02-07 12:58:05
@Pramod
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Pramod :
2014-02-07 09:19:24
@konrad krysteki: I don't understand why I am getting wrong answer. Here my program passed those test cases \n
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anurag garg:
2014-02-06 09:24:35
whooo AC in 0.00 Sec easy if you know the mathematics |
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shiv prasad chabarval:
2014-02-05 22:39:46
@Konrad Krystecki please tell me why i m getting WA. my code is working for all test cases. is n>=0 ?? |
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Bhavik:
2014-02-05 19:14:52
@lakshman: yes my code is also giving 599999..but still wa!!
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[Lakshman]:
2014-02-05 16:22:19
WFFFFF so many wrong answer but AC now. Last edit: 2014-02-06 13:46:42 |
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Bhavik:
2014-02-05 11:42:18
and n>=0??
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Added by: | Konrad Krystecki |
Date: | 2014-02-04 |
Time limit: | 1s |
Source limit: | 50000B |
Memory limit: | 1536MB |
Cluster: | Cube (Intel G860) |
Languages: | All except: ASM64 |