IDC1948 - Identity crisis
For every given number n we define x(n) as distance from n to the first number after n in form of 99...99. For example x(100)=899, x(45)=54, etc. Given several n numbers you have to find the Zp, where x(n) ≡ n (mod p).
Input
First line of input contains one number T (T < 20) - the number of test cases. In each of the next T lines contains one number each to represent n (0 < n < 30000000).
Output
In each line you have to write one number - the least p > 1 that x(n) ≡ n (mod p). If there is no such p the line should contain -1.
Example
Input: 2 234 5 Output: 3 -1
Explanation
x(234)=765. 765 mod 3=0, 234 mod 3=0 => 765 ≡ 234 (mod 3)
hide comments
Anshul Singhal:
2014-07-08 23:01:17
@Konrad Krystecki what is the x(n) for n=99.....Is it 900 or 0 ......Please reply fast Last edit: 2014-07-08 23:09:21 |
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P_Quantum:
2014-06-02 20:40:21
nice!! |
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[Lakshman]:
2014-05-24 14:15:33
@Tarun Garg So give a try to http://www.spoj.com/problems/LKID |
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Tarun Garg:
2014-05-24 12:40:44
seive,prime,elementary maths..:D |
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[Lakshman]:
2014-03-28 20:13:06
After solving this you may try http://www.spoj.com/problems/LKID with hard constraints. Last edit: 2014-03-29 03:39:57 |
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nikhil_nihal:
2014-03-24 05:20:59
unlucky 13..
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Jumpy:
2014-02-10 07:25:31
don't read comments they'll make you confuse only check the output of @Mostafa |
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RIVU DAS:
2014-02-08 10:18:56
Good ques!! |
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[Lakshman]:
2014-02-08 04:25:43
@ Mehmet Inal I think there is no math only the proper algorithm which Mitch is talking about, I was also confused with that comment |
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mehmetin:
2014-02-08 02:49:04
I had already AC'ed in 0.00s with something I use a lot, but I wonder if it can be done in one formula and O(1), doing maths, as some people pointed out. Last edit: 2014-02-08 02:51:05 |
Added by: | Konrad Krystecki |
Date: | 2014-02-04 |
Time limit: | 1s |
Source limit: | 50000B |
Memory limit: | 1536MB |
Cluster: | Cube (Intel G860) |
Languages: | All except: ASM64 |