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WILLITST - Will it ever stop |
When Bob was in library in University of Warsaw he saw on one of facades caption :"Will it ever stop?" and below some mysterious code:
while n > 1 if n mod 2 = 0 then n := n / 2 else n := 3 * n + 3
Help him finding it out !
Input
In first line one number n ≤ 1014.
Output
Print "TAK" if program will stop, otherwise print "NIE"
Example
Input: 4 Output: TAK
Added by: | Krzysztof Lewko |
Date: | 2011-11-09 |
Time limit: | 0.906s |
Source limit: | 50000B |
Memory limit: | 1536MB |
Cluster: | Cube (Intel G860) |
Languages: | All except: ASM64 |
Resource: | AMPPZ 2011 |
hide comments
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2016-06-14 19:19:43 suraj
can't get O(1) solution,help me |
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2016-06-12 07:38:34
collatz conjecture-all u need to know |
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2016-06-11 19:06:13
dont use float or double it gives WA , in some testcases. can't figure out why sol in O(1) |
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2016-05-21 18:31:17
It is a slight modified form of collatz conjecture, but this problem illustrates that how a slight modification can solve a problem so easily. |
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2016-01-29 17:42:46
O(1) solution, check if n <= 1 || n & (n-1) == 0 |
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2016-01-19 19:10:43 Bijoy Rahman Arif
WC: O(log2(n)) : this is the best solution I guess. |
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2015-12-22 21:23:49
same algo in pyth 2.7 got AC but got RE in c++ |
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2015-12-22 07:57:30
easy one.... |
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2015-12-11 08:14:48 hmp
simply use vector....insert all changing n...check if n repeats or not |
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2015-11-13 10:54:30 sri
ac with O(logn) |