WILLITST - Will it ever stop

When Bob was in library in University of Warsaw he saw on one of facades caption :"Will it ever stop?" and below some mysterious code:

while n > 1
  if n mod 2 = 0 then
    n:=n/2
  else
    n:=3*n+3

Help him finding it out !

Input

In first line one number n<=10^14.

Output

Print "TAK" if program will stop, otherwise print "NIE"

Example

Input:
4

Output:
TAK

Added by:Krzysztof Lewko
Date:2011-11-09
Time limit:0.906s
Source limit:50000B
Memory limit:1536MB
Cluster: Cube (Intel G860)
Languages:All except: ASM64
Resource:AMPPZ 2011

hide comments
2019-06-28 13:41:38
I am getting WA in 18th case ,i am using floor(log(n)/log(2))==ceil(log(n)/log(2)) ,what is going wrong here
2019-06-02 09:25:42
AC in one go,just need to check whether the number is multiple of two or not
2019-05-25 21:02:06
very simple no need for for any bitwise and condition just take a array and check whether number repeat or not . :)
2019-04-25 18:09:50


Last edit: 2019-04-25 19:52:22
2019-04-19 18:58:58
Anyone getting WA when using BigInteger and BigInteger.and() in java to check if n=2^k ?
2019-03-29 12:23:32
why is log floor and ceil combination giving wrong ans in c
2019-03-22 19:02:40
if(n>1&&ceil(log2(n))==floor(log2(n)))
cout<<"TAK";
else
//not gonna spoil main part XD
2019-01-23 17:06:48
c++ just two lines of code ,
think the advantage of floor,ceil function and logarithm.
2019-01-14 19:19:21
Check For case <=1 and simple logic
2018-12-14 23:16:16
AC in one go...Observe the pattern.
© Spoj.com. All Rights Reserved. Spoj uses Sphere Engine™ © by Sphere Research Labs.