ONEZERO - Ones and zeros

Certain positive integers have their decimal representation consisting only of ones and zeros, and having at least one digit one, e.g. 101. If a positive integer does not have such a property, one can try to multiply it by some positive integer to find out whether the product has this property.

Input

Number K of test cases (K is approximately 1000);
In each of the next K lines there is one integer n (1 ≤ n ≤ 20000)

Output

For each test case, your program should compute the smallest multiple of the number n consisting only of digits 1 and 0 (beginning with 1).

Example

Input:
3
17
11011
17

Output:
11101
11011
11101

Added by:Paweł Dobrzycki
Date:2005-05-26
Time limit:8s
Source limit:4096B
Memory limit:1536MB
Cluster: Cube (Intel G860)
Languages:All except: NODEJS PERL6 VB.NET
Resource:II Polish Olympiad in Informatics, Ist Stage

hide comments
2017-01-20 15:26:54
Great question on bfs :)
2017-01-07 14:43:53
best question on bfs ^_^
2017-01-04 21:15:17
nice question!! beware of-
1. long long overflow...use strings
2. try testcase 999,9999
3. modular arithmetic
2016-10-25 14:39:02
really ,cool logic! though i couldn't crack :P


Last edit: 2016-10-25 14:39:24
2016-10-16 18:16:41
instead of using bfs, we can use a counter. counter is basically a number counter.
but when u notice carefully, 1 -> 1, 2 -> 10, 3 -> 11, 4 -> 100 .... the binary representation of the counter value converted into equivalent decimal value can help us solve the problem. eg when value of counter is 5 -> 101 in binary, the number which we want would be 101 in decimal.
2016-09-03 16:51:31
BFS + Backtracking !
AC ! :)
2016-09-02 17:55:18 Sarthak Munshi
storing string or integer is trivial . Just store the remainder of leftchild%n and rightchild%n and check each of those to be 0 .
2016-08-19 12:39:17
backtracking :)

Last edit: 2016-08-19 12:56:01
2016-08-14 12:39:19
weak test cases
try 999.
2016-08-12 19:26:40
Got AC in one, 0,98
Check modular arithmetic
https://brilliant.org/wiki/modular-arithmetic/
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