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ONEZERO - Ones and zeros |
Certain positive integers have their decimal representation consisting only of ones and zeros, and having at least one digit one, e.g. 101. If a positive integer does not have such a property, one can try to multiply it by some positive integer to find out whether the product has this property.
Input
Number K of test cases (K is approximately 1000);
In each of the next K lines there is one integer n (1 ≤ n ≤ 20000)
Output
For each test case, your program should compute the smallest multiple of the number n consisting only of digits 1 and 0 (beginning with 1).
Example
Input: 3 17 11011 17 Output: 11101 11011 11101
Added by: | Paweł Dobrzycki |
Date: | 2005-05-26 |
Time limit: | 8s |
Source limit: | 4096B |
Memory limit: | 1536MB |
Cluster: | Cube (Intel G860) |
Languages: | All except: NODEJS PERL6 VB.NET |
Resource: | II Polish Olympiad in Informatics, Ist Stage |
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2020-04-08 10:31:07
1.learn how to compute mod of a big number using string. 2.use bfs |
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2020-03-11 08:33:21
A really good question to attempt. Extremely good concept to keep a track of the mod values. |
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2019-11-17 21:46:57
You don't need long division, you can simply mod the whole time with the number in input and remember the actual number only as a string and when the modded number becomes zero you return the string. |
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2019-08-25 09:51:10
Make sure to push s0 before s1, since s0<s1... |
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2019-05-14 21:37:57 cegprakash
can also be solved using a famous 2 letter algorithm xD Last edit: 2019-05-14 21:38:22 |
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2019-05-06 13:11:01
My code was not working for test case 99 and 999. I wasted around 1 hour thinking of some optimization. But later came to know that the test cases are very weak. very disappointed |
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2019-03-20 09:08:01
Great problem. A lot of optimizion you have to do. Got it in 0.22s. |
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2019-01-21 15:01:48
Nice problem , BFS + MODULAR ARITHMATIC =AC Last edit: 2019-01-21 15:02:03 |
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2018-10-16 11:07:39
wow just wow !! *__* |
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2018-07-22 14:15:05
If one is using C++ then for numbers like n=19999,19953, etc. the multiples will exceed the limit of int and eventually you will have to use string. You will have to create a separate function for longDivision. If one is using python then it is very easy problem for python users. For C++ users the approach is like this: 1. Code to generate binary numbers -- this is simple bfs problem. 2. Perform long division. Last edit: 2018-07-22 14:15:45 |