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OLOLO - Onotole needs your help |
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Onotole has a lot of pyani. Each pyani has a number, writing on it. Pyanis with equal numbers are indistinguishable. Onotole knows everything, so, he knows that each pyani appeared twice, and only one pyani is unique. He wants to get вздръжни эффект, and he needs the unique pyani. Given the list of pyanis denote which one of them appeared once (it is guaranteed that other pyanis appeared twice). |
Input
First line of input contains number of pyanis N <= 500 000. Next N lines contain a single positive integer 1 <= Pi <= 10^9.
Output
Output one positive integer on pyani, which appeared once.
Example
Input:
3
1
8
1
Output: 8
Onotole has found not optimal AC algorithms, so all solutions will be rejudged. He is watching you.
| Added by: | Efim |
| Date: | 2010-11-04 |
| Time limit: | 1s |
| Source limit: | 50000B |
| Memory limit: | 1536MB |
| Cluster: | Cube (Intel G860) |
| Languages: | All except: ASM64 |
hide comments
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2015-12-11 12:48:34
Thank u @Abishek yr suggestion for fast io worked |
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2015-11-22 18:44:32
use scanf to read values in c++ |
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2015-11-11 16:02:51 sumit suthar
Just XOR... :) |
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2015-10-28 23:07:32
If using Sort method use Scanf instead of CIN. |
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2015-10-10 18:14:28 shivam
if using cin or cout,set sync_with_stdio(false); cin.tie(NULL); |
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2015-10-07 16:27:05 nap11
is this possible in java? |
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2015-09-26 18:03:58 DeviSree
same sol TLE in python anyway nice question |
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2015-09-20 13:17:29 Sarthak Munshi
ridiculous problem statement ! |
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2015-09-19 09:13:49
xor method is easier ....way... |
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2015-09-18 04:26:54 MSK
did it in java tle :( same in c ac... Not fair for java... |
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