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OLOLO - Onotole needs your help |
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Onotole has a lot of pyani. Each pyani has a number, writing on it. Pyanis with equal numbers are indistinguishable. Onotole knows everything, so, he knows that each pyani appeared twice, and only one pyani is unique. He wants to get вздръжни эффект, and he needs the unique pyani. Given the list of pyanis denote which one of them appeared once (it is guaranteed that other pyanis appeared twice). |
Input
First line of input contains number of pyanis N <= 500 000. Next N lines contain a single positive integer 1 <= Pi <= 10^9.
Output
Output one positive integer on pyani, which appeared once.
Example
Input:
3
1
8
1
Output: 8
Onotole has found not optimal AC algorithms, so all solutions will be rejudged. He is watching you.
| Added by: | Efim |
| Date: | 2010-11-04 |
| Time limit: | 1s |
| Source limit: | 50000B |
| Memory limit: | 1536MB |
| Cluster: | Cube (Intel G860) |
| Languages: | All except: ASM64 |
hide comments
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2017-08-16 20:04:11
Unlike most other problems, do not put a newline at the end of your answer... it will count as wrong. |
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2017-07-04 07:56:34
For a=a^t ,it is giving segmentation fault if i take 'a' as an integer.Could anybody explain me why this is happening |
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2017-06-03 20:18:42
Use printf or scanf if you use c++ instead of cin and cout to avoid TLE!! |
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2017-06-02 14:00:48
use scanf or printf or fastIO lines ios_base::sync_with_stdio(0);cin.tie(NULL); |
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2017-05-28 11:00:10
EAsy man took the mistook array size as 10^5 instead of 5*10^5 costed me sigsev...use xor basics :) |
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2017-05-21 08:09:59
Easy! |
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2017-03-25 17:46:01
CAKEWALK :) |
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2017-03-20 06:23:42
Great problem to learn the xor gate!! :') |
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2017-03-07 17:04:41
MF semicolons give me 3 WA. Simple Use of XOR,Learnt XOR. |
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2017-02-15 19:01:29
AC in one GO! |
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