INVCNT - Inversion Count

Let A[0 ... n - 1] be an array of n distinct positive integers. If i < j and A[i] > A[j] then the pair (i, j) is called an inversion of A. Given n and an array A your task is to find the number of inversions of A.

Input

The first line contains t, the number of testcases followed by a blank space. Each of the t tests start with a number n (n ≤ 200000). Then n + 1 lines follow. In the ith line a number A[i - 1] is given (A[i - 1] ≤ 107). The (n + 1)th line is a blank space.

Output

For every test output one line giving the number of inversions of A.

Example

Input:
2

3
3
1
2

5
2
3
8
6
1


Output:
2
5

Added by:Paranoid Android
Date:2010-03-06
Time limit:3.599s
Source limit:50000B
Memory limit:1536MB
Cluster: Cube (Intel G860)
Languages:All except: PERL6

hide comments
2015-11-02 20:37:04
superb use of divide and conquer ;)
2015-10-20 22:49:41 Advitiya
YODANESS~INVCNT :) mergesort
2015-10-19 10:53:37
how unsorted the array is!!! :)
2015-10-15 13:31:48 Mateusz Kwasniak
Of course both div&conq and BIT will work. Good one.

Last edit: 2015-10-15 13:32:09
2015-10-14 06:01:18
datatype of count to be noted (long long int), caused me 2 WA!
2015-09-23 21:14:33 Sarthak Munshi
2 WA, 2 RE , 1 CE . But then AC using BIT !
2015-09-18 23:45:58 Nitin Tiwari
accepted in first go
2015-09-15 15:01:38 MSK
solved using bit... awesome feeling.... :)
2015-09-05 19:00:39 thirupathireddy
long long int .....................:) leads to wrong answer.........
2015-09-03 19:15:18 codeprince
@pvsmpraveen... 5 is number of elements that shouldn't be considered
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