INVCNT - Inversion Count

Let A[0...n - 1] be an array of n distinct positive integers. If i < j and A[i] > A[j] then the pair (i, j) is called an inversion of A. Given n and an array A your task is to find the number of inversions of A.

Input

The first line contains t, the number of testcases followed by a blank space. Each of the t tests start with a number n (n <= 200000). Then n + 1 lines follow. In the ith line a number A[i - 1] is given (A[i - 1] <= 10^7). The (n + 1)th line is a blank space.

Output

For every test output one line giving the number of inversions of A.

Example

Input:
2

3
3
1
2

5
2
3
8
6
1


Output:
2
5

Added by:Paranoid Android
Date:2010-03-06
Time limit:3.599s
Source limit:50000B
Memory limit:1536MB
Cluster: Cube (Intel G860)
Languages:All except: PERL6

hide comments
2016-05-22 16:15:21 Mallika Agarwal
Can an admin please help me out with some test cases on which problem is not working?
Edit - Resolved now.

Last edit: 2016-05-23 00:35:43
2016-05-18 08:26:26
did first using o(n^2)....time limit exceeded ! :( now realised have to use merge sort
2016-05-16 12:08:59
did using modified merge_sort ..can anybody tell me how to implement using BIT???
2016-05-13 13:43:35
a very nice question with the use of BIT...(use long long)
2016-05-13 10:56:39
solved by Merge Sort in 1st go :) But i want to solve it using BIT. Pls :( give me some hints to think about BIT for this problem
2016-05-12 21:43:24
use unsigned long long int for counting inversions.
2016-04-28 02:43:41
Modification of Merge Sort. Did the same question from CLRS :)
2016-04-17 10:43:09
Read BIT from ch2 of "CP by Steven Halim" and it will be a piece of cake. :)
2016-03-18 05:32:48


Last edit: 2016-03-19 12:07:28
2016-02-27 13:10:49 arthur
Can be solved using segment, BIT, range trees. Also try and solve LIS using segment trees. All solutions should be O(nlgn)
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