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HORRIBLE - Horrible Queries |
World is getting more evil and it's getting tougher to get into the Evil League of Evil. Since the legendary Bad Horse has retired, now you have to correctly answer the evil questions of Dr. Horrible, who has a PhD in horribleness (but not in Computer Science). You are given an array of N elements, which are initially all 0. After that you will be given C commands. They are -
* 0 p q v - you have to add v to all numbers in the range of p to q (inclusive), where p and q are two indexes of the array.
* 1 p q - output a line containing a single integer which is the sum of all the array elements between p and q (inclusive)
Input
In the first line you'll be given T, number of test cases.
Each test case will start with N (N <= 100 000) and C (C <= 100 000). After that you'll be given C commands in the format as mentioned above. 1 <= p, q <= N and 1 <= v <= 10^7.
Output
Print the answers of the queries.
Example
Input:
1
8 6
0 2 4 26
0 4 8 80
0 4 5 20
1 8 8
0 5 7 14
1 4 8
Output:
80
508
Added by: | Iqram Mahmud |
Date: | 2010-12-04 |
Time limit: | 2.329s |
Source limit: | 50000B |
Memory limit: | 1536MB |
Cluster: | Cube (Intel G860) |
Languages: | All except: ASM64 |
Resource: | Own. Thanks to Emir Habul. |
hide comments
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2015-06-22 13:33:58 sourabh
BIT it is :D |
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2015-05-28 18:41:38 harkirat
Ac in first go! |
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2015-05-26 06:03:11 Dhawal Harkawat
seems like v>10^7 ;( |
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2015-05-23 17:40:40 appy
why v need to be long long ?? 1<=v<=1e7 |
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2015-05-22 10:02:50 Seshadri R
@ Rishab Banerjee: v is specified to be <= 10^7. During recursive calls, it remains an invariant and hence it cannot go beyond 10^7. This is well within an int limit (32-bits). So, may I know why long long int is required for v? |
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2015-04-15 17:19:50 Abhilash
used BIT. think in terms of addition and multiplication for range updates in BIT |
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2015-04-08 11:58:34 Anonymous
There is A bug within this judge i think i submitted like 50 times and every time was a WA on test 22 i hate this site |
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2015-04-02 09:13:12 xxbloodysantaxx
BIT is so fast :) Lesser space... and everything ... Morover we can still use Segment tree without Lazy propagation just as in the case of BIT ... Lazy propagation is more useful in questions such as Flipping Coins |
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2015-03-31 13:51:48 Malfple
Because of this problem, now i know how to update and query range using BIT :) |
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2015-03-28 20:12:59 GAURAV CHANDEL
Using segment tree + lazy propagation AC Having problem , visit http://se7so.blogspot.in/2012/12/segment-trees-and-lazy-propagation.html very good tutorial |