HORRIBLE - Horrible Queries

World is getting more evil and it's getting tougher to get into the Evil League of Evil. Since the legendary Bad Horse has retired, now you have to correctly answer the evil questions of Dr. Horrible, who has a PhD in horribleness (but not in Computer Science). You are given an array of N elements, which are initially all 0. After that you will be given C commands. They are -

* 0 p q v - you have to add v to all numbers in the range of p to q (inclusive), where p and q are two indexes of the array.

* 1 p q - output a line containing a single integer which is the sum of all the array elements between p and q (inclusive)

 

Input

In the first line you'll be given T, number of test cases.

Each test case will start with N (N <= 100 000) and C (C <= 100 000). After that you'll be given C commands in the format as mentioned above. 1 <= p, q <= N and 1 <= v <= 10^7.

Output

Print the answers of the queries.

Example

Input:
1
8 6
0 2 4 26
0 4 8 80
0 4 5 20
1 8 8
0 5 7 14
1 4 8

Output:
80
508

Added by:Iqram Mahmud
Date:2010-12-04
Time limit:2.329s
Source limit:50000B
Memory limit:1536MB
Cluster: Cube (Intel G860)
Languages:All except: ASM64
Resource:Own. Thanks to Emir Habul.

hide comments
2024-06-14 23:53:52
take long long by adding value to the node
2023-10-21 10:42:19
TLE ;(
2023-07-06 11:46:48
EZ AC ONE GO
TRIVIAL
Please make harder test cases, my O(n^4) solution passed
2022-11-29 18:27:05
Make sure to clear the arrays :)
2022-06-07 13:28:52
Don't forget to update the lazy to 0 after every testcase
2022-04-23 06:36:01
If anyone is facing any problem with segment tree size you can try out submitting here
** It got accepted there but here gave wa
NB: use long long instead of int

Last edit: 2023-05-12 22:46:04
2022-02-03 18:29:54
AC in 1 go, Solved using fenwick tree
2021-08-27 19:48:21 Jean-Ralph Aviles
Don't use 32 bit integers anywhere.
2021-08-25 19:02:12
Solved with segment tree + lazy propagation, just gotta remember about those long longs
2021-07-19 03:13:51
1 segment tree AC in 2 go
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