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FREQUENT - Frequent values |
You are given a sequence of n integers a1, a2 ... an in non-decreasing order. In addition to that, you are given several queries consisting of indices i and j (1 ≤ i ≤ j ≤ n). For each query, determine the most frequent value among the integers ai ... aj.
Input Specification
The input consists of several test cases. Each test case starts with a line containing two integers n and q (1 ≤ n, q ≤ 100000). The next line contains n integers a1 ... an (-100000 ≤ ai ≤ 100000, for each i ∈ {1 ... n}) separated by spaces. You can assume that for each i ∈ {1 ... n-1}: ai ≤ ai+1. The following q lines contain one query each, consisting of two integers i and j (1 ≤ i ≤ j ≤ n), which indicate the boundary indices for the query.
The last test case is followed by a line containing a single 0.
Output Specification
For each query, print one line with one integer: The number of occurrences of the most frequent value within the given range.
Sample Input
10 3 -1 -1 1 1 1 1 3 10 10 10 2 3 1 10 5 10 0
Sample Output
1 4 3
A naive algorithm may not run in time!
Added by: | Adrian Kuegel |
Date: | 2007-07-06 |
Time limit: | 1s |
Source limit: | 50000B |
Memory limit: | 1536MB |
Cluster: | Cube (Intel G860) |
Languages: | All except: ERL JS-RHINO NODEJS PERL6 VB.NET |
Resource: | University of Ulm Local Contest 2007 |
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2019-06-09 14:27:42
*Segment tree size [ 4*N] *1 base indexing |
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2019-06-04 05:10:04
oh, forgot that this problem has multiple test case :")) Last edit: 2019-06-04 05:10:48 |
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2019-05-29 10:37:18
Nice problem!! Try GSS1 first, if you get stuck |
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2019-05-29 08:44:43
Read the question carefully, it has multiple test cases and last test case ends with 0, Wasted so much time because of this :/ |
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2019-02-07 13:04:08 krishna Murari
handling the 0 case cost half my day |
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2019-01-27 20:51:09
same as Uva 11235 :) |
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2018-11-28 16:47:03
solving GSS1 first really helped a lot! |
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2018-08-01 20:12:41 DOT
Phew! At last, AC. Didn't understand multiple test cases will come until 0 is entered. @thekidnamedme, same for me. 125th answer there is different from my solution. |
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2018-06-10 08:11:29
AC in one Go . Solved GSS1 before. |
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2018-06-07 13:13:09
Interesting find. My AC solution differs from that on spoj toolkit for testcase #23 (1 conflict). http://spojtoolkit.com/history/FREQUENT |