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FREQUENT - Frequent values |
You are given a sequence of n integers a1, a2 ... an in non-decreasing order. In addition to that, you are given several queries consisting of indices i and j (1 ≤ i ≤ j ≤ n). For each query, determine the most frequent value among the integers ai ... aj.
Input Specification
The input consists of several test cases. Each test case starts with a line containing two integers n and q (1 ≤ n, q ≤ 100000). The next line contains n integers a1 ... an (-100000 ≤ ai ≤ 100000, for each i ∈ {1 ... n}) separated by spaces. You can assume that for each i ∈ {1 ... n-1}: ai ≤ ai+1. The following q lines contain one query each, consisting of two integers i and j (1 ≤ i ≤ j ≤ n), which indicate the boundary indices for the query.
The last test case is followed by a line containing a single 0.
Output Specification
For each query, print one line with one integer: The number of occurrences of the most frequent value within the given range.
Sample Input
10 3 -1 -1 1 1 1 1 3 10 10 10 2 3 1 10 5 10 0
Sample Output
1 4 3
A naive algorithm may not run in time!
Added by: | Adrian Kuegel |
Date: | 2007-07-06 |
Time limit: | 1s |
Source limit: | 50000B |
Memory limit: | 1536MB |
Cluster: | Cube (Intel G860) |
Languages: | All except: ERL JS-RHINO NODEJS PERL6 VB.NET |
Resource: | University of Ulm Local Contest 2007 |
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2020-06-26 09:43:06
I have realized now that java is not for competitive programming. |
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2020-06-15 16:03:27
non-decreasing order helps a lot!!! |
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2020-06-06 07:16:49
tle in java:( |
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2020-04-28 07:36:52
Spoj really gives me a hard time on I/O |
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2020-04-09 00:24:37 Mohammad Ali
using scanf literally got my solution accepted. used scanf and cout. |
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2020-03-07 02:35:45
It costed me 4WA for this and a lot of time. Be careful for the last zero input. Last edit: 2020-03-07 02:36:15 |
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2019-12-29 21:31:34
Nice problem |
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2019-11-04 10:23:30
nice problem, try GSS1 after this... |
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2019-10-31 19:13:04
AC in one go.....After reading the comments!! |
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2019-07-01 01:27:21
good problem Last edit: 2019-07-01 01:27:40 |