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FACVSPOW - Factorial vs Power |
Consider two integer sequences f(n) = n! and g(n) = an, where n is a positive integer. For any integer a > 1 the second sequence is greater than the first for a finite number of values. But starting from some integer k, f(n) is greater than g(n) for all n >= k. You are to find the least positive value of n for which f(n) > g(n), for a given positive integer a > 1.
Input
The first line of the input contains number t – the amount of tests. Then t test descriptions follow. Each test consist of a single number a.
Constraints
1 <= t <= 100000
2 <= a <= 106
Output
For each test print the least positive value of n for which f(n) > g(n).
Example
Input: 3 2 3 4 Output: 4 7 9
Added by: | Spooky |
Date: | 2009-11-01 |
Time limit: | 1s |
Source limit: | 50000B |
Memory limit: | 1536MB |
Cluster: | Cube (Intel G860) |
Languages: | All except: ASM64 NODEJS OBJC PERL6 SQLITE VB.NET |
Resource: | Advancement Autumn 2009, http://sevolymp.uuuq.com/ |
hide comments
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2014-04-30 07:21:01 sarelfeniel
Good problem. No idea how the fastest people are doing it. Must be secrets of mathematics I do not know. Some good test cases from the forum that helped me --edit(francky)--> Please do not add test cases, those in description should be enough. @Francky I guess... honestly it takes < 3 seconds to go to the forum to find additional cases. Last edit: 2014-05-04 10:11:40 |
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2013-07-01 09:42:20 Hasil Sharma
newton raphson or something else to be used by any chance ? |
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2013-04-11 08:10:52 raunakrocks
esy math...no its programming..AC!! |
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2013-02-17 07:43:29 Inspiron
nice prob.... |
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2012-07-20 14:35:23 devu
Sab Funde Baji Hai .. Think Programming ,not mathematics ,mathematics part is simple.... |
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2011-03-10 13:51:08 sandeep pandey
avoid stirling appx.(due to precision issue). think mathematics:-)) |
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2011-02-01 07:51:45 bashrc is back
I am getting TLE.....Am i missing something? |
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2010-11-03 11:45:04 jacob
can anyone with an AC give me some test cases for very large numbers ~10^5 or ~10^6 i am getting a wrong answer using stirling approximation |
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2010-08-29 09:11:52 Curiosa
dont calculate n! and a^n. just use some mathematics |
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2010-06-25 00:17:59 :(){ :|: & };:
It is possible to get an Accepted verdict by using Stirling approximation :) Last edit: 2010-06-25 00:19:42 |