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BITDIFF - Bit Difference |
Given an integer array of N integers, find the sum of bit differences in all the pairs that can be formed from array elements. Bit difference of a pair (x, y) is the count of different bits at the same positions in binary representations of x and y. For example, bit difference for 2 and 7 is 2. Binary representation of 2 is 010 and 7 is 111 (first and last bits differ in two numbers).
Input
Input begins with a line containing an integer T (1<=T<=100), denoting the number of test cases. Then T test cases follow. Each test case begins with a line containing an integer N (1<=N<=10000), denoting the number of integers in the array, followed by a line containing N space separated 32-bit integers.
Output
For each test case, output a single line in the format Case X: Y, where X denotes the test case number and Y denotes the sum of bit differences in all the pairs that can be formed from array elements modulo 10000007.
Example
Input: 1 4 3 2 1 4 Output: Case 1: 22
Added by: | imranziad |
Date: | 2015-11-24 |
Time limit: | 0.5s |
Source limit: | 50000B |
Memory limit: | 1536MB |
Cluster: | Cube (Intel G860) |
Languages: | All except: ASM64 GOSU JS-MONKEY |
Resource: | AIUB CS Fest 2015 (H.M. Mehrab) |
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2020-09-02 10:08:58
Bitset made it simpler;) |
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2018-04-29 09:41:41
note that 1e7+7! |
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2018-02-14 06:37:53
Enjoyed solving it, but thumbs down for idiotic timelimit. Got AC and optimised the runtime by gradually dumbing my code down. No lesson in this. |
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2017-08-12 15:40:16
O(33nt) not 32 because of input :) |
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2017-02-13 09:21:07
easy one forget to print newline cost me 1 WA |
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2016-12-28 08:01:02
how on earth O(n)? |
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2016-12-22 19:56:58 Mayank Agarwal
take care of ordered pairs!! |
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2016-08-24 02:26:09
Extremely strict time limit costed me 3 tle's don't take long long unnecessarily |
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2016-08-09 17:53:26
ios::sync_with_stdio(false); AC |
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2016-03-14 17:06:36
Does this ask for the sum of the Hamming weight of the XOR of all pairs or the sum of the XOR-s of all pairs?? |