SPOJ.com - Problem RGB7002

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RGB7002 - Гурвалжин

Өгөгдсөн гурвалжны периметрийг ол.

Input

Гурвалжны талууд бүхэл тоогоор нэг мөрөнд зайгаар тусгаарлагдан өгөгдөнө.

Output

Гурвалжны периметр.

Example

Input:
3 4 5

Output:
12

Submit solution!

Нэмсэн:	Bataa
Огноо:	2011-01-15
Хугацааны хязгаарлалт:	1s
Эх кодын хэмжээний хязгаарлалт:	50000B
Memory limit:	1536MB
Cluster:	Cube (Intel G860)
Програмчлалын хэлүүд:	ADA95 ASM32 BASH BF C NCSHARP CSHARP C++ 4.3.2 CPP C99 CLPS LISP sbcl LISP clisp D ERL FORTRAN HASK ICON ICK JAVA JS-RHINO JULIA LUA NEM NICE OCAML PAS-GPC PAS-FPC PERL PHP PIKE PRLG-swi PYTHON PYPY3 PYTHON3 RUBY SCALA SCM guile ST TCL WHITESPACE

hide comments

2023-08-15 18:08:20
#include <iostream>
using namespace std;

int main() {

long long a,b,c,i,t;
cin>>t;
for(i=0;i<t;i=i+1){
cin>>a>>b>>c;
if((a>=b && c%2==1)||(a>b))
cout<<"First"<<endl;
else
cout<<"Second"<<endl;
}

return 0;
}

2023-08-14 07:02:26
#include<bits/stdc++.h>
using namespace std;
int main(){
int a[10000],b,c,d,e,f,g,h,i,j,x,y,k,z,t=0,s=0,n;
cin>>n;
for(i=1;i<=n;i++){
cin>>a[i];
if(a[i]==1){
cout<<3<<endl;
}
if(a[i]==2){
cout<<2<<endl;
}
if(a[i]>2&&a[i]%2==1){
cout<<1<<endl;
}
if(a[i]>2&&a[i]%2==0){
cout<<0<<endl;
}

}
return 0;
}
Judged Example Tests

2023-06-15 12:48:13
java code
import java.util.*;

public class Main {

public static void main(String[] args) {

Scanner scanner=new Scanner(System.in);
int a=scanner.nextInt();
int b=scanner.nextInt();
int c=scanner.nextInt();
System.out.println(a+b+c);
}
}

Last edit: 2023-06-15 12:48:40

2023-06-15 12:23:17
public class Main {
public static void main(String[] args) {
int buf,byter,core,result;
buf=3; byter=4;core=5;
result = buf+byter+core;
System.out.println(result);
}
}

2023-05-23 14:08:56
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2023-05-15 08:08:27
.. -- / - .. .-. . -..

2023-05-15 03:02:18
zest fest in here bruh

2023-05-15 02:56:16
ogay

Last edit: 2023-05-15 03:04:23

2023-05-10 09:51:48
2023-03-24 02:52:14
#include <iostream>

using namespace std;

int main()
{
int a[1000],n,i,s=0,b[1000],t=0;
cin>>n;
for (i=1;i<=n;i++) {
cin>>a[i];
s+=a[i];
}
for (i=1;i<=n;i++)
if (s%a[i]==0 && s/a[i]==n) {
t=t+1;
b[t]=i;
}
if (t!=0) {
cout<<t<<endl;
for (i=1;i<=t;i++){
cout<<b[i]<<" ";
}}
else
cout<<0<<endl;
cout<<" ";

return 0;
}

2023-05-06 14:14:03
ta nar bugd gomo

АЛГОРИТМЫН ЦАГААН ТОЛГОЙ

RGB7002 - Гурвалжин

Input

Output

Example