Problem hidden
|This problem was hidden by Editorial Board member probably because it has incorrect language|version or invalid test data, or description of the problem is not clear.|

RGB7002 - Гурвалжин

Өгөгдсөн гурвалжны периметрийг ол.

Input

Гурвалжны талууд бүхэл тоогоор нэг мөрөнд зайгаар тусгаарлагдан өгөгдөнө.

Output

Гурвалжны периметр.

Example

Input:
3 4 5

Output:
12


Нэмсэн:Bataa
Огноо:2011-01-15
Хугацааны хязгаарлалт:1s
Эх кодын хэмжээний хязгаарлалт:50000B
Memory limit:1536MB
Cluster: Cube (Intel G860)
Програмчлалын хэлүүд:ADA95 ASM32 BASH BF C NCSHARP CSHARP C++ 4.3.2 CPP C99 CLPS LISP sbcl LISP clisp D ERL FORTRAN HASK ICON ICK JAVA JS-RHINO JULIA LUA NEM NICE OCAML PAS-GPC PAS-FPC PERL PHP PIKE PRLG-swi PYTHON PYPY3 PYTHON3 RUBY SCALA SCM guile ST TCL WHITESPACE

hide comments
2023-10-30 11:59:05
https://tetr.io/#QRAU
2023-10-27 13:40:58
https://tetr.io/#DFLZ
2023-10-27 13:34:50
https://tetr.io/#ZUYR
2023-10-27 13:24:54
https://tetr.io/#MJHG
2023-10-27 13:16:52
https://tetr.io/#JXPQ
2023-10-27 13:08:55
#include<iostream>
using namespace std;
int main(){
int n,t,a,b,c,d,k;
cin>>a>>b;
k=a-b;
d=b-a;
if (a>b){
cout<<b<<" "<<k/2;
}
else{
cout<<a<<" "<<d/2;
}
}
2023-10-27 13:04:35
https://tetr.io/#DHLA
2023-10-27 13:01:35
https://tetr.io/#GHXL
2023-10-27 12:10:22
#include <iostream>
using namespace std;

int main() {

int x,a,b,m=0,c;
cin>>x>>a>>b>>c;
if (x%2==0){
m=m+x;
}
if (a%2==0){
m=m+a;
}
if (b%2==0){
m=m+b;
}

cout<<m;
return 0;
}
2023-10-27 11:58:38
#include <iostream>
using namespace std;

int main() {

int a, b, c, d, e, n, k;
cin>>n>>k;
cout<<n+(k-n%k);
return 0;
}
© Spoj.com. All Rights Reserved. Spoj uses Sphere Engine™ © by Sphere Research Labs.