SUMSUMS - Summing Sums
The N (1 ≤ N ≤ 50,000) cows, conveniently numbered 1, 2, ..., N, are trying to learn some encryption algorithms. After studying a few examples, they have decided to make one of their own! However, they are not very experienced at this, so their algorithm is very simple:
Each cow i is given a starting number Ci (0 ≤ Ci < 90,000,000), and then all the cows perform the following process in parallel:
- First, each cow finds the sum of the numbers of the other N-1 cows.
- After all cows are finished, each cow replaces her number with the sum she computed. To avoid very large numbers, the cows will keep track of their numbers modulo 98,765,431.
They told Canmuu the moose about it in November; he was quite impressed. Then one foggy Christmas Eve, Canmuu came to say:
"Your algorithm is too easy to break! You should repeat it T (1 ≤ T ≤ 1,414,213,562) times instead."
Obviously, the cows were very frustrated with having to perform so many repetitions of the same boring algorithm, so after many hours of arguing, Canmuu and the cows reached a compromise: You are to calculate the numbers after the encryption is performed!
Input
- Line 1: Two space-separated integers: N and T.
- Lines 2..N+1: Line i+1 contains a single integer: Ci.
Output
- Lines 1..N: Line i contains a single integer representing the number of cow i (modulo 98,765,431) at the end of the encryption.
Example
Input: 3 4 1 0 4 Output: 26 25 29
The following is a table of the cows' numbers for each turn:
Cows' numbers Turn Cow1 Cow2 Cow3 0 1 0 4 1 4 5 1 2 6 5 9 3 14 15 11 4 26 25 29Warning: large input/output data.
hide comments
rouge_kitty:
2022-08-23 21:51:28
<snip> check it out if you are getting a WA/TLE after doing matrix exponentiation
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hetp111:
2019-12-22 22:05:03
Very strict Time limit...! |
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smso:
2019-11-26 04:55:03
Use matrix exponentiation. There are only 2 distinct values (in the diagonal and off-diagonal respectively) in any intermediate step. Python3 is able to pass the grader. |
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rocky1729:
2019-11-15 11:22:39
@agarwal117
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kesh4281:
2019-08-09 13:44:18
even if u get a wrong on test case #1, the program still runs until last case. So don't get confused that u r only getting WA in last case only.
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agrawal117:
2019-08-01 16:33:22
very nice problem!!
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aayush_b1999:
2019-07-10 23:05:42
i wasn't doing modulus for sum of initial values.that's why i was getting wrong answer in test 14. so there might be problem with how you are doing mod. hope it helps other's problem. Last edit: 2019-07-11 07:21:41 |
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grucha78:
2019-06-02 16:51:15
Is it possible to get "Accepted" in Java? My program runs locally 0.03s for maximum set size, yet I get TLE. |
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infyy:
2018-06-01 10:15:44
Getting WA in last test case even though I have used 98765431 |
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druh:
2017-12-01 14:24:58
WA on 14 :( Help PLEASE!
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Added by: | Neal Wu |
Date: | 2008-05-28 |
Time limit: | 1s |
Source limit: | 50000B |
Memory limit: | 1536MB |
Cluster: | Cube (Intel G860) |
Languages: | All except: ERL JS-RHINO |
Resource: | USACO Chn 2007 |