SUMDEC2 - Sum the Decimal-part II
A much easier version of this problem can be found here-SUMDEC1. In case you haven't tried it out, try the first part.
In this problem, you are given a number. You need to output the sum of the first 1000 decimal places of the square-root of the number (ignore the integral part).
For example-if the given number is 2. The square-root of 2 is 1.4142135623..... So, ignore the number before decimal (1 in this case) and add the first 1000 digits after decimal and output them as result. (4482 in this case.
NOTE: If the number is a perfect square, the output should be 0.
Input
the first line of input consist of t (the number of test cases).
t lines follow-Each line consist of a non-negative integer n.
Output
Output in separate lines the result corresponding to integer n.
Constraints
1 ≤ t ≤ 1001 ≤ n ≤ 100000
Example
Input: 2 4 2 Output: 0 4482
hide comments
nadstratosfer:
2017-10-05 08:43:24
No newline after last result gives WA. WTF! |
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Pranay:
2017-09-18 20:46:33
cake walk in python |
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muzzlers:
2016-01-25 15:40:42
TAKE PRECISION 2-3 RANK BIGGER THAN 100000
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iharsh234:
2016-01-22 09:13:13
testcase:-
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sairampola:
2016-01-12 14:31:30
getting NZEC in python 2.7 .. can u check the input ? |
Added by: | Prateek Agarwal |
Date: | 2016-01-10 |
Time limit: | 1s |
Source limit: | 50000B |
Memory limit: | 1536MB |
Cluster: | Cube (Intel G860) |
Languages: | All except: ASM64 GOSU JS-MONKEY |