SAS003 - Apoorv Loves Primes
Given two arrays A and B of size n and x. Apoorv is given an empty array P. He has to fill the array according to the following conditions:
for each i in range (0 to x-1) { if b[i] is negative (insert the subarray from A[abs(B[i]] to A[n-1] in P at the end) else (insert the subarray from A[0]to A[B[i]] in P at the end) }
Since Apoorv loves Prime numbers He wants to know the Kth prime number in P after the above operation is completed.
So given q queries Apoorv has to report the kth prime number in it. If kth prime doesn't exist print -1.
Note: Both A and B are 0 indexed. abs stands for absolute value.
Constraints:
1<=n<=100000
1<=x<=100000
1<=A[i]<=1000000
0<=abs(B[i])<=n-1
1<=q<=10000
1<=k<=10000000000
Input
First line will contain n size of A.
Second line will contain n space separated integers denoting A[i].
Third line will contain x denoting size of B.
Fourth line will containĀ x space separated integers denoting B[i].
Fifth line will contain q denoting number of queries.
Sixth line will contain q space separated integers denoting k.
Output
Print q lines denoting output for each query.
Example
Input: 3 2 3 4 1 2 3 1 2 3 Output: 2 3 -1
Explanation:
P is [2,3,4] so for k=1 answer is 2, for k=2 answer is 3, for k=3 answer=-1 because 3rd prime number doesn't exist.
hide comments
Sushovan Sen:
2019-06-06 10:06:06
@sas1905 Can you please tell where my solution is failing? Last edit: 2019-06-06 10:14:07 |
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aman_sachin200:
2018-06-18 14:09:51
Nice One SAS!! |
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nadstratosfer:
2018-06-09 22:07:35
Mehmet, try this:
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mehmetin:
2018-06-09 18:04:28
We have to find kth prime in array p according to insertion order or according to index of ordered primes?
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nadstratosfer:
2018-06-06 23:57:38
Is it meant to be solvable with Python, Sasmit? My mem use is quite disturbing but the non-O(1)-answers approach will TLE for sure. Please increase the limit slightly if I'm following the right path.
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hodobox:
2018-06-06 14:18:37
Two comments: the code in the statement would probably look better pre-formatted. The constraints on B[i] are actually 0 <= abs(B[i]) <= n-1.
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Added by: | sas1905 |
Date: | 2018-06-06 |
Time limit: | 1s |
Source limit: | 50000B |
Memory limit: | 1536MB |
Cluster: | Cube (Intel G860) |
Languages: | All |
Resource: | Other Contest. |