PUCMM210 - A Summatory
f(n) is defined as: f(n) = 13+23+33+...+n3, so it is the sum of the cubes of all natural numbers up to n.
In this problem you are about to compute,
f(1) + f(2) + f(3) + ... + f(n)
Input
The first line is an integer T (1 ≤ T ≤ 100,000), denoting the number of test cases. Then, T test cases follow.
For each test case, there is an integer n (1 ≤ n ≤ 1,000,000) written in one line.
Output
For each test case output the result of the summatory function described above.
Since this number could be very large, output the answer modulo 1,000,000,003.
Example
Input:
3
2
10
3
Output:
10
7942
46
hide comments
omar alkattan:
2013-10-25 00:47:50
AC :)
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BLANKRK:
2013-09-23 20:38:35
huhh.. finaly done!! |
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Sanchit Manchanda:
2013-08-02 05:55:54
Getting SIGSEGV for this code. Any idea whats wrongs.
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***:
2013-07-22 17:43:59
ans for n=1000000? |
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shiv prasad chabarval:
2013-06-23 18:27:22
mod caused 11 WA's... huh AC with a very bad timing 2.02. |
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Gaurav Khewal:
2013-06-16 16:03:30
my century!!!!
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rafiki93:
2013-05-18 08:51:14
can you please give some big number test cases.have used mod literally everywhere but still getting wrong ans |
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yaswanth:
2013-05-01 16:36:11
very simple!! similar to http://www.spoj.com/problems/SUMPOWK1/ |
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Arika Saputro:
2013-04-30 02:46:40
i reduce from 11 branch to 2 branch and the time only reduced by 0.01 =( |
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[Lakshman]:
2013-04-03 06:31:21
finally AC after several TLE,used precomputation to pass the time limit. |
Added by: | Olson Ortiz |
Date: | 2012-05-24 |
Time limit: | 1s |
Source limit: | 50000B |
Memory limit: | 1536MB |
Cluster: | Cube (Intel G860) |
Languages: | All |
Resource: | Used in 2nd dominican ACM-ICPC Warm Up 2012 Competition in PUCMM |