ONEZERO - Ones and zeros
Certain positive integers have their decimal representation consisting only of ones and zeros, and having at least one digit one, e.g. 101. If a positive integer does not have such a property, one can try to multiply it by some positive integer to find out whether the product has this property.
Input
Number K of test cases (K is approximately 1000);
In each of the next K lines there is one integer n (1 ≤ n ≤ 20000)
Output
For each test case, your program should compute the smallest multiple of the number n consisting only of digits 1 and 0 (beginning with 1).
Example
Input: 3 17 11011 17 Output: 11101 11011 11101
hide comments
cheesy:
2020-04-28 15:28:44
Is it guaranteed that an answer will exist?
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ajaygupta007:
2020-04-08 10:31:07
1.learn how to compute mod of a big number using string.
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abhinav_jain02:
2020-03-11 08:33:21
A really good question to attempt.
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fran_1024:
2019-11-17 21:46:57
You don't need long division, you can simply mod the whole time with the number in input and remember the actual number only as a string and when the modded number becomes zero you return the string. |
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hetp111:
2019-08-25 09:51:10
Make sure to push s0 before s1, since s0<s1... |
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cegprakash:
2019-05-14 21:37:57
can also be solved using a famous 2 letter algorithm xD Last edit: 2019-05-14 21:38:22 |
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aditya_305:
2019-05-06 13:11:01
My code was not working for test case 99 and 999. I wasted around 1 hour thinking of some optimization. But later came to know that the test cases are very weak. very disappointed
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letuantam96:
2019-03-20 09:08:01
Great problem. A lot of optimizion you have to do. Got it in 0.22s. |
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ab_biswas09:
2019-01-21 15:01:48
Nice problem , BFS + MODULAR ARITHMATIC =AC Last edit: 2019-01-21 15:02:03 |
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jmr99:
2018-10-16 11:07:39
wow just wow !! *__* |
Added by: | Paweł Dobrzycki |
Date: | 2005-05-26 |
Time limit: | 8s |
Source limit: | 4096B |
Memory limit: | 1536MB |
Cluster: | Cube (Intel G860) |
Languages: | All except: NODEJS PERL6 VB.NET |
Resource: | II Polish Olympiad in Informatics, Ist Stage |