MULTQ3 - Multiples of 3
There are N numbers a[0], a[1] ... a[N - 1]. Initially all are 0. You have to perform two types of operations :
- Increase the numbers between indices A and B (inclusive) by 1. This is represented by the command "0 A B"
- Answer how many numbers between indices A and B (inclusive) are divisible by 3. This is represented by the command "1 A B".
Input
The first line contains two integers, N and Q. Each of the next Q lines are either of the form "0 A B" or "1 A B" as mentioned above.
Output
Output 1 line for each of the queries of the form "1 A B" containing the required answer for the corresponding query.
Sample
Input: 4 7 1 0 3 0 1 2 0 1 3 1 0 0 0 0 3 1 3 3 1 0 3 Output: 4 1 0 2
Constraints
1 ≤ N ≤ 100000
1 ≤ Q ≤ 100000
0 ≤ A ≤ B ≤ N - 1
hide comments
ajay_5097:
2016-05-23 19:38:37
IT felt so good !
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epsilon:
2015-08-26 13:48:38
thanks to vimarsh for fast i/o
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karthik1997:
2015-08-09 01:01:10
o(n) algo +fast i/o needed
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shakaal:
2015-01-12 22:03:25
truly teaches u the concept fastIO,lazy,segment tree and finally AC |
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Eddy Cael:
2015-01-07 21:02:11
No necesary fast I/O. I got AC with ordinary Segment Tree + Lazy + cin/cout in 4.60 s.
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Deepanker Aggarwal:
2014-12-31 01:40:47
Time Limit for languages like Java should be increased
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Vaibhav Gosain:
2014-12-24 09:08:32
time limit is a little too tight ;-) |
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anonymous:
2014-07-03 01:14:13
same code AC in C++ gives tle in c... |
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GURVINDER SINGH:
2014-05-28 16:03:23
AC in first attempt no need of fast i/o
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Added by: | Varun Jalan |
Date: | 2010-09-12 |
Time limit: | 1s |
Source limit: | 50000B |
Memory limit: | 1536MB |
Cluster: | Cube (Intel G860) |
Languages: | All except: NODEJS OBJC VB.NET |
Resource: | own problem |