MPOWER - Power it!
Wersja polska | English version |
For a given numbers x, y and n calculate
i.e. a number r such that 0 <= r < n and n | (xy - r).
Input
t [the number of test cases <= 10]
x y n [2 <= x, n <= 230, 0 <= y <= 230 - easy (1010000 - hard)
First two test cases are easy, the following four test cases are hard. Threshold is 2 pts (the problem is accepted).
Output
r [such that xy = r (mod n)]
Example 1 (easy)
Input: 2 54015779 489100829 472960975 827371214 966345673 443599139 Output: 350431544 391669493
Example 2 (hard)
Input: 1 29809803 47901912849872523461864631327232122 1008098565 Output: 718185534
hide comments
nati__22:
2021-06-16 12:26:08
AC in one go ... 10 points |
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dewa251202:
2018-10-02 10:15:26
O(len(y)^2) only got 2 pts |
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alanturing13:
2017-03-30 18:31:51
python's pow method seems to work
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shubh809:
2016-10-19 15:01:04
10 points after some efforts |
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Abhishek:
2016-09-17 13:41:41
Pythons default mod pow beats the question, so implementing fast modular exponentiation should do it |
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Md. Istiyak ahmed:
2013-12-11 17:40:56
I solved the easy one with bigmod which is log(n) . But for harder how can I handle the large value of y ? Last edit: 2013-12-11 17:45:44 |
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Micha³ Ma³afiejski:
2009-12-16 07:19:55
2<=x,n<=2^30, 0 <= y <= 2^30 - easy
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Paulo Roberto Santos de Sousa:
2009-03-12 09:33:57
Thanks! I think that the best algorithm for solve that problem is the fast modular exponentiation, but my code get just TLE. Someone can help me? Last edit: 2009-03-12 09:33:57 |
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[Trichromatic] XilinX:
2009-03-12 08:39:25
Maybe - My program (in both C and Python) can haddle test case like that. |
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Paulo Roberto Santos de Sousa:
2009-03-12 07:52:13
For easy tests 2<=x,n<=2^30 e 0<=y<=2^30.
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Added by: | mima |
Date: | 2006-02-27 |
Time limit: | 1s-8.932s |
Source limit: | 50000B |
Memory limit: | 1536MB |
Cluster: | Cube (Intel G860) |
Languages: | All |