MINCOUNT - Move To Invert
A triangle made of coins of height h is as follows:
- It has h coins at the base and h-1 coins one level above base and so on. (Coins are placed as shown in the figure below.)
- At the top-most level there will be only one coin.
Now given h, the task is to invert this triangle by moving the minimum number of coins.
For example when h=4 triangle is:
For h=4 at least 3 coins must be moved to invert it.
Input
In the first line N will be given and then N lines follow with each line having a integer which is the height of triangle in that test case. (0 ≤ h < 1010.)
Output
For each test case output in a separate line the minimum number of moves required to invert the triangle. Output fits in long long data type.
Example
Input: 1 3 Output: 2
hide comments
Javier (dreivaj):
2009-08-28 03:46:11
Some outputs
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LeppyR64:
2009-06-08 16:41:57
top row = 1, second row = 2 3, third row = 4 5 6, fourth row = 7 8 9 10 Solution: move 7 to the left of 2, move 10 to the right of 3, move 1 below 8&9 Last edit: 2009-06-08 16:42:32 |
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~!(*(@*!@^&:
2009-06-03 05:29:50
someone can explain the example in the image? i need 4 moves for h=4 (image), but they need 3.
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Added by: | Abhilash I |
Date: | 2006-12-16 |
Time limit: | 1s |
Source limit: | 50000B |
Memory limit: | 1536MB |
Cluster: | Cube (Intel G860) |
Languages: | All except: ERL JS-RHINO |
Resource: | IIIT Hyderabad Local Programming Contest |