In this problem you will be given a half-circle. The half-circle’s radius is r. You can take any point A on the half-circle and draw 2 lines from the point to the two sides of the diameter(AB and AC). Let the sum of square of one line’s length and the other line’s length is s

Like in the figure s = AB² + AC. And BC = 2r.

Now given r you have to find the maximum value of s. That is you have to find point A such that AB² + AC is maximum.

Input

First line of the test case will be the number of test case T (1 ≤ T ≤ 1000). Then T lines follows. On each line you will find a integer number r (1 ≤ r ≤ 1000000); each representing the radius of the half-circle.

Output

For each input line, print a line containing "Case I: ", where I is the test case number and the maximum value of s. Print 2 digit after decimal (Errors should be less then .01).

Example

Sample Input:
1
1

Sample Output:
Case 1: 4.25

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	sparky: 2014-12-02 15:13:34 All the test cases are integers. You don't need double to input. Make sure your output is in the right syntax: "Case 1: "+value
	HITESH GARG: 2014-12-01 16:46:51 test case also have float radius value... easy one..
	tictactoecoder: 2014-10-23 09:25:01 @rituraj I just followed your testcase :D and got AC 1st time :D thnx bro :D
	jinkies: 2014-10-15 11:42:00 pretty easy, if you have the right info
	Vamsi Krishna Avula: 2014-10-13 17:33:49 radius as given in question is just integer, no float values are given. Last edit: 2015-01-13 14:15:41
	vikax: 2014-09-19 10:08:23 easy one simple math.......
	Saurabh Shukla: 2014-09-18 23:15:25 Basic maths.Took me back to the good old days of my high school :)
	funky: 2014-09-05 12:16:01 wtf!! got 2 wa for case instead of Case
	eightnoteight: 2014-09-03 17:19:32 very very simple question...
	surayans tiwari(http://bit.ly/1EPzcpv): 2014-08-30 12:49:10 +0.25 easiest ques