LASTDIG - The last digit
Nestor was doing the work of his math class about three days but he is tired of make operations a lot and he should deliver his task tomorrow. His math’s teacher gives him two numbers a and b. The problem consist of finding the last digit of the potency of base a and index b. Help Nestor with his problem. You are given two integer numbers: the base a (0 <= a <= 20) and the index b (0 <= b <= 2,147,483,000), a and b both are not 0. You have to find the last digit of ab.
Input
The first line of input contains an integer t, the number of test cases (t <= 30). t test cases follow. For each test case will appear a and b separated by space.
Output
For each test case output an integer per line representing the result.
Example
Input: 2 3 10 6 2
Output: 9 6
hide comments
Samil Vargas:
2013-12-17 15:11:45
ohh god i tried this problem so many time and though that this shit was wrong but keep trying in my number 11 it work cause i saw a little problem try all the test cases from 0 0 till 10 5 |
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[Lakshman]:
2013-12-10 05:55:22
@Washington Please remove the below code. Last edit: 2013-12-10 08:13:50 |
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Washington:
2013-12-10 01:19:14
Just kidding... |
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Washington:
2013-12-10 01:17:53
Never was so easy:
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Ankit Jain:
2013-12-09 23:45:40
ac in 1 go...simple if u know how to calculate powers efficiently..:) |
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Shashank Gupta:
2013-11-06 06:17:33
Easy AC in 0.00 time in C. :) Just use arrays and modulo operator. And remember that anything to the power of 0 is 1. |
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Sourabh Verma:
2013-11-05 13:49:17
Accepted! 1^0 = 1 and 0^1 = 0.
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isif:
2013-10-22 21:30:20
can anyone send long tests? ex: a=12,14,16 and b = 2,147,483,000 |
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alampata:
2013-10-22 17:16:53
I am getting correct answer for all the test cases tried...even special ones...
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Shashank:
2013-09-02 17:11:51
Getting wrong ans though code is correct. anyone help me please |
Added by: | Jose Daniel Rodriguez Morales |
Date: | 2008-12-01 |
Time limit: | 1s |
Source limit: | 700B |
Memory limit: | 1536MB |
Cluster: | Cube (Intel G860) |
Languages: | All except: GOSU |
Resource: | Own |