JNEXT - Just Next !!!
DevG likes too much fun to do with numbers. Once his friend Arya came and gave him a challenge, he gave DevG an array of digits which is forming a number currently (will be called as given number). DevG was challanged to find the just next greater number which can be formed using digits of given number. Now DevG needs your help to find that just next greater number and win the challenge.
Input
The first line have t number of test cases (1 <= t <= 100). In next 2*t lines for each test case first there is number n (1 <= n <= 1000000) which denotes the number of digits in given number and next line contains n digits of given number separated by space.
Output
Print the just next greater number if possible else print -1 in one line for each test case.
Note : There will be no test case which contains zero in starting digits of any given number.
Example
Input: 2 5 1 5 4 8 3 10 1 4 7 4 5 8 4 1 2 6 Output: 15834 1474584162
hide comments
pissedoff:
2020-05-14 11:04:25
I have run below test case and results are fine.
|
|
mahmud9:
2020-05-08 14:00:26
use array and next_permuation. It will ac in 1 go. :) |
|
ck_17:
2020-05-07 10:06:44
For those who are getting wrong answers try this test case
|
|
heemmanshuu:
2020-04-30 14:42:28
my code works for the given test cases and some of my own, but i'm getting a WA here. HELP. |
|
amit_dubey99:
2020-04-30 10:47:11
TLEEEEEEE |
|
stan_vj:
2020-04-15 17:53:16
@sayal_hajare
|
|
sachin_19:
2020-04-15 13:10:15
Easy one just use next permutation |
|
acean_2kacer:
2020-04-10 16:23:14
i found this question under topic heading stack. how do we solve it using stack?
|
|
manish_thakur:
2020-03-27 11:51:06
answer wiil be -1 for cases like : 1,2,333,4444 |
|
klmo:
2020-03-26 06:53:46
O(n) in java giving tle. Need to use faster ip/op? |
Added by: | ! include(L.ppt) |
Date: | 2012-08-31 |
Time limit: | 1.297s |
Source limit: | 50000B |
Memory limit: | 1536MB |
Cluster: | Cube (Intel G860) |
Languages: | All except: ASM64 |
Resource: | MNNIT OPC 31-08-2012 |