INVESORT - Inversion Sort
You have just bought an old fashioned jukebox that can hold 10 music albums. Albums are maintained as a sequence, each album represented by a unique lowercase letter between “a” and “j”, inclusive. The jukebox allows you to select a subsequence of contiguous albums and a mechanical arm inverts that part of the sequence. For instance, if the current sequence is “abcdefghij” and you select the subsequence “bcd”, the result of the inversion would be “adcbefghij”. Soon you notice that it is possible to get the albums into any desired order using simply inversions. However, you are interested in doing so with the minimum number of operations. Given the current order and a desired order of the 10 music albums, find the minimum number of inversion operations needed to obtain the desired order.
Input
The input contains several test cases, each one described in a single line. The line contains two strings C and D separated by a single space, representing the current and desired orders of the music albums, respectively. Each of the strings has exactly 10 characters and contains the characters of “abcdefghij” in some order. The last line of the input contains two asterisks (“*”) separated by a single space and should not be processed as a test case.
Output
For each test case output a single line with an integer representing the minimum number of inversions needed to transform the current order given by C, into the desired order given by D.
Example
Input: abcdefghij adcbefghij abcdefghij abcdefghij bcdaefghji beagfcdhji * * Output: 1 0 2
hide comments
ButaBil:
2012-08-09 15:48:15
There is around 900 tests |
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ymGXX:
2010-11-27 03:53:39
How many test cases are there? Last edit: 2010-11-27 03:53:57 |
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যোবায়ের:
2010-09-01 00:28:16
1. b(cdae)fghji
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Anirban Saha:
2010-09-01 00:28:16
can someone please explain test case 3? |
Added by: | Pablo Ariel Heiber |
Date: | 2010-08-24 |
Time limit: | 89.26s |
Source limit: | 50000B |
Memory limit: | 1536MB |
Cluster: | Cube (Intel G860) |
Languages: | All except: NODEJS OBJC PERL6 VB.NET |
Resource: | FCEyN UBA ICPC Selection 2009 |