HAP01 - Play with Binary Numbers
Let S be the binary representation of an integer. We define two functions a(i) and b(i) such that:
- a(i) = Number of occurrences of '1' at odd positions of S,
- b(i) = Number of occurrences of '1' at even positions of S.
For example: for integer 19, S = 10011, so a(19) = 2 and b(19) = 1.
Input
First line contains an integer T, the number of test cases. Then T lines follow. On each line, you will be given three integers M, N, K.
Output
For each test case output a single integer R, where R is the number of integers 'i' between M and N (both inclusive) such that absolute difference of a(i) and b(i) is equal to K. The answer to each each test case should be on a separate line.
Constraints
T ≤ 50
1 ≤ M < N ≤ 1019
1 ≤ N - M ≤ 106
0 ≤ K ≤ 50
Example
Input: 1 1 10 2 Output: 2
hide comments
I know nothing:
2014-02-12 21:38:49
awsome problem
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Martijn Muijsers:
2013-10-30 23:56:28
@Lakshay does it matter? You can switch meanings of a and b if you want.
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Lakshay Singhal:
2013-08-11 10:30:22
odd pos counted from left or right? |
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mystique_blue:
2013-08-01 18:27:28
hehe at a place i had a int i instead of long long ... earned a lot of tles today. |
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Amit RC:
2013-07-31 11:18:16
I wasn't expecting brute force to be accepted..but it seems it easily is. |
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abdelkarim:
2013-05-26 17:36:51
i think there some problem in spoj so i got compilation error 6 times ! |
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abdou_93:
2013-05-25 12:38:42
so easy ...:D |
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tuhin:
2013-05-22 21:35:37
@ :-) AWESOME PROBLEM
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Aradhya:
2013-05-19 19:08:16
@hindustan:: please provide a test case or plz check my submission id 9298476 :) |
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:-):
2013-04-18 16:11:41
@ RuPp$
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Added by: | :-) |
Date: | 2013-04-16 |
Time limit: | 1.201s |
Source limit: | 50000B |
Memory limit: | 1536MB |
Cluster: | Cube (Intel G860) |
Languages: | All |
Resource: | own |