HANGOVER - Hangover
How far can you make a stack of cards overhang a table? If you have one card, you can create a maximum overhang of half a card length. (We're assuming that the cards must be perpendicular to the table.) With two cards you can make the top card overhang the bottom one by half a card length, and the bottom one overhang the table by a third of a card length, for a total maximum overhang of 1/2 + 1/3 = 5/6 card lengths. In general you can make n cards overhang by 1/2 + 1/3 + 1/4 + ... + 1/(n + 1) card lengths, where the top card overhangs the second by 1/2, the second overhangs tha third by 1/3, the third overhangs the fourth by 1/4, etc., and the bottom card overhangs the table by 1/(n + 1). This is illustrated in the figure below.
Input
The input consists of one or more test cases, followed by a line containing the number 0.00 that signals the end of the input. Each test case is a single line containing a positive floating-point number c whose value is at least 0.01 and at most 5.20; c will contain exactly three digits.
Output
For each test case, output the minimum number of cards necessary to achieve an overhang of at least c card lengths. Use the exact output format shown in the examples.
Input: 1.00 3.71 0.04 5.19 0.00 Output: 3 card(s) 61 card(s) 1 card(s) 273 card(s)
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sgtfdotfcrfn:
2016-08-16 00:21:30
AC in one go! I had a few troubles writing the code at first, but this problem is actually pretty simple... I really enjoyed it! =) Last edit: 2016-08-16 00:22:10 |
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Sarvajeet Suman:
2016-08-02 06:09:21
AC in 1 GO .......... Easy Problem. |
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shubham9466:
2016-07-09 14:59:56
brute force!!
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baadshah_:
2016-06-21 10:48:46
AC!! in one GO!!!
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shady313:
2016-06-20 18:40:33
floats comparison is an important factor here...otherwise very simple. |
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vineetpratik:
2016-06-10 19:37:42
got 2WA just of output format :/ |
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manish3749:
2016-05-27 21:22:00
easiest i have ever solve on spoj
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jitendrakk:
2016-05-13 21:05:37
why this card(s)? WA multiple times. :(
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shashankch292:
2016-04-19 17:01:40
wasted half an hour understanding this text......very simple problem.....really very easy :)
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giriprasad kemburu:
2016-03-07 08:01:16
Ac in 1 Go...my 12th :) |
Added by: | Wanderley Guimarăes |
Date: | 2006-06-09 |
Time limit: | 1s |
Source limit: | 50000B |
Memory limit: | 1536MB |
Cluster: | Cube (Intel G860) |
Languages: | All except: ERL JS-RHINO NODEJS PERL6 VB.NET |
Resource: | ACM Mid Central Regionals 2001 |