GIRLSNBS - Girls and Boys
There are G girl students and B boy students in a class that is about to graduate. You need to arrange them in a single row for the graduation. To give a better impression of diversity, you want to avoid having too many girls or too many boys seating consecutively. You decided to arrange the students in order to minimize the gender regularity. The gender regularity of an arrangement is the maximum number of students of the same gender (all girls or all boys) that appear consecutively. Given G and B, calculate the minimum gender regularity among all possible arrangements.
Input
Each test case is described using a single line. The line contains two integers G and B representing the number of girls and boys in the class, respectively (0 ≤ G, B ≤ 1000). The end of input is indicated with a line containing the number −1 twice.
Output
For each test case, output a single line with a single integer representing the minimum gender regularity that an arrangement of G girls and B boys can have.
Example
Input:
10 10
5 1
0 1000
-1 -1
Output:
1
3
1000
hide comments
avi_kumar15:
2020-05-24 11:39:54
use float if u have ceil function *pacefalm* |
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sahil_19:
2020-04-23 14:17:05
Hint: Use gapping method like in pnc |
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mo_affan01:
2020-02-05 09:02:29
try to construct a formula by taking different cases
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mrmajumder:
2020-01-31 16:35:57
Pigeon Hole Principle :D |
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Tomek Jarosik:
2020-01-08 19:10:25
no need to handle edge-cases if you have a correct formula |
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manish_thakur:
2019-12-17 14:11:15
take care of case 0 0
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naman_mawandia:
2019-08-04 07:29:29
case 1 0 or 0 1
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aryan29:
2019-06-03 18:10:10
Easiest |
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shaakal:
2019-05-22 12:29:37
simple first divide minimum+1 with max and take ceil |
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aj_254:
2019-05-06 06:49:30
5 line code in python always remember if input is 5 1 total six student so you put 1 in mid that 2 partitions but thats why you have to divide it by min(g,b) +1 that give you right anwer ez pz ac in one go because showoff is good for you mental health |
Added by: | Pablo Ariel Heiber |
Date: | 2010-09-27 |
Time limit: | 2s |
Source limit: | 50000B |
Memory limit: | 1536MB |
Cluster: | Cube (Intel G860) |
Languages: | All except: ASM64 NODEJS OBJC VB.NET |
Resource: | FCEyN UBA ICPC Selection 2010 |