EOD - Even Odd Digit
Given a number N. Count every digit even and odd number from N. Your task is to find which count is maximum, even or odd. You can assume that even or odd count is not same.
Input
Input starts with an integer T (T≤ 1000), denoting the number of test cases. Each case is a integer N (0 ≤ N ≤ 107).
Output
For each test case, print which is maximum count even or odd. When even is maximum count then print “even” (without the quotes) otherwise print “odd” (without the quotes).
Example
Input: 3 125 10000000 789 Output: odd even odd
Problem setter: Shipu Ahamed, Dept. of CSE
Bangladesh University of Business and Technology (BUBT)
Added by: | Shipu Ahamed |
Date: | 2013-09-13 |
Time limit: | 1s |
Source limit: | 50000B |
Memory limit: | 1536MB |
Cluster: | Cube (Intel G860) |
Languages: | All except: ASM64 |