EC_P - Critical Edges
This time I will not bore you with a long and boring sentence. Give a connected graph, you must find all the edges that are critical, in other words you must find the edges which when removed divide the graph.
Input
The first line contains a integer NC (1 ≤ NC ≤ 200), the number of test cases. Then follow NC test cases.
Each case begins with two integers N (1 ≤ N ≤ 700) and M (N-1 ≤ M ≤ N * (N-1) / 2), the number of nodes and the number of edges respectively. Then follow M lines, each with a pair of integers a b (1 ≤ a, b ≤ N) indicate that between the node a and the node b there is a edge.
Output
For each test case print the list of ways to protect the following format:
Caso #n t x1 y2 x2 y2 ... xt yt
Where n is the case number (starting from 1), t is the total of critical edges, list elements xi yi indicates, for each line, there is a critical edge between the node xi and node yi (1 ≤ xi
If there isn't any critical edge print: "Sin bloqueos" (quotes for clarity).
Example
Input: 3 5 4 1 2 4 2 2 3 4 5 5 5 1 2 1 3 3 2 3 4 5 4 4 6 1 3 1 4 2 1 3 2 4 2 4 3 Output: Caso #1 4 1 2 2 3 2 4 4 5 Caso #2 2 3 4 4 5 Caso #3 Sin bloqueos
hide comments
luvkumbi:
2020-02-20 19:40:19
Cool....learned to detect bridges in a graph....while inserting bridges in final ans.....see that xi<yi and also print edges in lexographically increasing order. |
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jerry_san:
2019-12-08 20:30:16
I am getting runtime error in this question. can someone help me with this |
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parsae:
2019-10-30 08:53:23
can anyone give a test case |
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scolar_fuad:
2019-09-25 15:00:37
(simpleBridege point problem )
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rishabh_jiit:
2019-08-29 19:12:15
Print "Caso" not "Case" .Cost me 4WA
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moeentm:
2019-08-14 14:47:50
EZZZZZZZZ,AC IN ONE GO,
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shubham97361:
2019-08-07 00:19:58
Xi < Yi must hold. |
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dishant107:
2019-07-27 16:28:22
In case of TLE, use scanf and printf instead of cin and cout. |
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surajkumar_cse:
2019-01-17 11:31:16
Here 'c' of Caso is in upper case . It took me around 1 hour to figure out what was going wrong with my code. |
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dipankar12:
2018-05-19 18:14:49
Time limit very strict for JAVA. Not even one submission.
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Added by: | Eddy Cael |
Date: | 2013-10-31 |
Time limit: | 0.100s |
Source limit: | 50000B |
Memory limit: | 1536MB |
Cluster: | Cube (Intel G860) |
Languages: | C-CLANG C NCSHARP C++ 4.3.2 CPP CPP14 CPP14-CLANG JAVA JULIA PYTHON PYPY3 PYTHON3 |