EASYMATH - EASY MATH
You will be given 4 numbers: n m a d.
find count of numbers between n and m (inclusive) not divisible by (a) or (a+d) or (a+2d) or (a+3d) or (a+4d).
Input
first line has number t - number of test cases.
each test case has 4 numbers n m a d.
Output
Single line having single number giving the count.
Constraints
1 <= n <= m <= 2^32
1 <= a <= 2^32
1 <= d <= 2^32
2 <= t <= 100
Example
Input: 3 1 10 2 2 20 100 3 3 100 1000 4 5 Output: 5 54 543
Also try the challenge version at www.spoj.com/problems/EASYMATC/
hide comments
Hussain:
2014-07-27 16:27:42
Very nice problem |
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excursionist:
2014-05-19 10:10:30
@vijay:= ur count variable containts old value update it to 0 after printing it for each test case |
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pvkcse:
2014-05-17 12:28:17
Any tricky case please...getting o/p in ideone but here it is WA... <snip> Last edit: 2023-05-18 20:38:00 |
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785227:
2014-02-21 16:50:43
Please check my submission ID 11100462
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pranjuldb:
2013-07-30 18:43:15
nice question... :) |
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Aayush Agarwal:
2013-06-01 15:24:21
@DEVIL D : the answer for the first test case should be 10 because it is said which are not divisible by a or a+d or a+2d.... so numbers upto 9 are not divisible by 10 and 10 is not divisible by 6 or 8 or 4.. so every number is counted in this manner. Last edit: 2013-06-01 15:25:22 |
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Saurabh Jain:
2012-07-29 13:04:43
@Devil D: i have checked a lot of test cases correctly on my system but here i'm getting WA.... could you please tell me reason for the same or test case for which my algo fails? |
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Abhishek Mishra:
2012-07-01 05:51:45
i think there is no test case for any extreme one..;) |
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Better late than never !!!:
2012-06-05 04:22:24
It's not at all easy :O |
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Ravi kishore :
2012-06-01 14:43:33
Nice problem!
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Added by: | Devil D |
Date: | 2012-04-17 |
Time limit: | 0.100s-1s |
Source limit: | 20000B |
Memory limit: | 1536MB |
Cluster: | Cube (Intel G860) |
Languages: | All except: ASM64 |
Resource: | Own |