DIVSUM - Divisor Summation
Given a natural number n (1 <= n <= 500000), please output the summation of all its proper divisors.
Definition: A proper divisor of a natural number is the divisor that is strictly less than the number.
e.g. number 20 has 5 proper divisors: 1, 2, 4, 5, 10, and the divisor summation is: 1 + 2 + 4 + 5 + 10 = 22.
Input
An integer stating the number of test cases (equal to about 200000), and that many lines follow, each containing one integer between 1 and 500000 inclusive.
Output
One integer each line: the divisor summation of the integer given respectively.
Example
Sample Input: 3 2 10 20 Sample Output: 1 8 22
Warning: large Input/Output data, be careful with certain languages
hide comments
darkhire21:
2015-08-10 20:31:35
At 3rd got AC |
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ROHIT Kumar:
2015-08-03 17:31:55
for 1 ans should be 0
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akash:
2015-08-02 17:13:33
runtime error..!
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ALi Ibrahim:
2015-07-26 22:16:15
Third Accepted, nice problem :) |
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ALi Ibrahim:
2015-07-26 15:12:01
amisha
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Piyush Deshmukh:
2015-07-17 08:13:27
AC in first attempt. For those who are struggling with TLE, My algo works in O(log(n)+sqrt(n)) in C, 0.12 sec. |
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scyth3r:
2015-07-15 13:54:19
Last edit: 2015-07-15 20:36:36 |
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scyth3r:
2015-07-15 08:35:38
Last edit: 2015-07-15 20:36:15 |
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QuickGun93:
2015-07-13 06:47:50
use c or c++ with long long. same logic in python gave tle |
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arcane_achal:
2015-07-06 12:50:55
I am getting the tle error can someone help
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Added by: | Neal Zane |
Date: | 2004-06-10 |
Time limit: | 3s |
Source limit: | 5000B |
Memory limit: | 1536MB |
Cluster: | Cube (Intel G860) |
Languages: | All |
Resource: | Neal Zane |