COMDIV - Number of common divisors
You will be given T (T<=10^6) pair of numbers. All you have to tell is the number of common divisors between two numbers in each pair.
Input
First line of input: T (Number of test cases)
In next T lines, each have one pair A B (0 < A, B <= 10^6)
Output
One integer describing number of common divisors between two numbers.
Example
Input: 3
100000 100000
12 24
747794 238336 Output: 36
6
2
hide comments
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Egor:
2011-06-27 16:46:07
Solution with 0(n/2 + lnln(n)) is ok on pascal =)
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Prateek Khandelwal:
2011-06-27 16:46:07
this is for sir Mir Wasi Ahmed,if you will take 10^6 test cases and each test case is "10^6 10^6" then the code i have submitted which is accepted by you will give tle but for your test cases my code is accepted..
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Vladimir Kirichenkoff:
2011-06-27 16:46:07
Yes |
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Seshadri R:
2011-06-27 16:46:07
Should 1 be always counted as one of the common divisors for the given pair? |
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[Retired]:
2011-06-27 16:46:07
TLE |
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:D:
2011-06-27 16:46:07
"will O(sqrt (min(x,y) ) pass?"
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Radhakrishnan Venkataramani:
2011-06-27 16:46:07
will O(sqrt (min(x,y) )
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Mir Wasi Ahmed:
2011-06-27 16:46:07
@purav: Many solutions including mine used only scanf and got Accepted. So people should not assume that they need fast IO.
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purav:
2011-06-27 16:46:07
i got TLE with scanf, had to use faster I/O to get acc |
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:(){ :|: & };::
2011-06-27 16:46:07
Nice test cases, I got few WA since I was too lame to check for integer overflows ;-) |
| Added by: | Mir Wasi Ahmed |
| Date: | 2010-10-31 |
| Time limit: | 0.600s |
| Source limit: | 50000B |
| Memory limit: | 1536MB |
| Cluster: | Cube (Intel G860) |
| Languages: | All except: ASM64 |
| Resource: | Own problem, used in UODA TST |
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