BUET19A - Mod
Gon and Killua is playing rock, paper, scissors game. Now they are bored with the traditional rules.
So, they think to change the rule. Each of them will say a number in lieu of using fingers.
Let a number be x:
- if x%3==0, it means ROCK.
- if x%3==1, it means PAPER.
- if x%3==2, it means SCISSORS.
The rest of the rules are the same:
- for ROCK and PAPER, PAPER will win,
- for ROCK and SCISSOR, ROCK will win,
- for PAPER and SCISSORS, SCISSORS will win.
- And if both of them are the same, it will be a DRAW.
Input
Input starts with an integer T, denoting the number of test cases.
Each case contains two integers X (Gon’s number) and Y (Killua’s number.)
1 <= T <= 100000
1 <= X, Y <= 100000
Output
For each case, if Gon win, print “GON”, else if KILLUA win, print “KILLUA” or if it is a draw, print “DRAW”.
Example
Input: 3 0 1 1 0 3 3 Output: KILLUA GON DRAW
Added by: | Anik |
Date: | 2019-01-28 |
Time limit: | 1s |
Source limit: | 50000B |
Memory limit: | 1536MB |
Cluster: | Cube (Intel G860) |
Languages: | C++ 4.3.2 |