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XXXXXXXX - Sum of Distinct Numbers |
You are given N numbers. You have to perform two kinds of operations:
U x y - x-th number becomes equal to y.
Q x y - calculate the sum of distinct numbers from x-th to y-th. It means that the sum for the set {1, 2, 3, 2, 7} will be equal to 13 (1+2+3+7).
Input
The first line of input contains an integer N. 1<=N<=50000
The second line consists of N numbers.
The third line consists of an integer Q. 1<=Q<=100000
The following Q lines will consist of queries of the form described in the task description.
All numbers in input will fit in the signed 32-bit type.
Output
Output an answer for every query of the second type.
Example
Input:
5
1 2 4 2 3
3
Q 2 4
U 4 7
Q 2 4
Output:
6
13
Hint: Time limit is ~ 1.5*(my program's execution time in the worst case)
Added by: | Sergey Kulik |
Date: | 2011-06-23 |
Time limit: | 1s |
Source limit: | 44444B |
Memory limit: | 1536MB |
Cluster: | Cube (Intel G860) |
Languages: | All except: ASM64 |
Resource: | Known problem |
hide comments
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2021-06-24 11:05:54
This can be solved by just simple square root decomposition + prefix sums. No need to use mo's algorithm. My code : <snip> [NG]: Yes we know you can do square root decomposition, as indicated by your comments in just about every problem on square root decomposition. Also, read the footer. Last edit: 2021-06-24 12:53:41 |
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2021-05-21 11:50:24
block size n^(2/3) + MO's algorithm with update + compression + long long ans -> AC |
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2020-08-05 13:21:34
Why compression is needed?? |
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2020-04-19 02:23:33
Unfairly for Java coders! |
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2020-03-08 11:21:00
Set the block size to n^(2/3) to avoid TLE If you are using MO's algorithm with update + compression. Last edit: 2020-03-08 11:21:21 |
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2019-03-10 10:28:05
MO with update + compression = AC for those who are getting WA at 20th test case try to use long long |
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2018-06-30 06:48:46
Seems like segment tree + dynamic segment tree is possible for this problem. |
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2017-12-16 00:18:17
Mo with update + compression....AC |
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2017-11-15 18:16:33
segment trees <3 |
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2017-08-31 20:25:22
Can this be solved using mo's algorithm using updates?...getting TLE :p |