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VPL2_AA - Luis Quest |
Luis is playing his old metroid game. Just a little while ago he pass trough a scenario where the room was filled with some amoeba-like creatures. The room started with some initial number of creatures, but they multiply their selves very quickly, because their growth rate is proportional to the number of creatures at a certain time. Luis took note about this fact, he wrote the number of creatures at the initial time, and then, after wait t time units, he wrote the new amount. Now Luis wants to know, for a certain number of creatures p, the exact time he has to be in the room to see that amount.
Input
The first line contains an integer T, which specifies the number of test cases. Then, will follow the descriptions of T test cases.
For each test case, there will be 2 lines, the first one will contain 4 integers, p0, p1, t and p. These numbers represents the initial amount of creatures, the second amount of creatures, the time units that Luis waited to see that change, and the number of creatures that Luis wants to see.
Output
For each input case you must print a single line containing the string "Scenario #i: " where i is the number of the test case (starting at one), and then the answer to the problem rounded to two decimal places. There will always be an answer.
Example
Input: 4 10 15 3 15 10 15 3 20 5 12 2 50 5 12 2 7 Output: Scenario #1: 3.00 Scenario #2: 5.13 Scenario #3: 5.26 Scenario #4: 0.77
Constraints
1 ≤ T, p0, p1, t, p ≤ 100
Added by: | Venezuelan Programming League |
Date: | 2013-06-22 |
Time limit: | 1s |
Source limit: | 50000B |
Memory limit: | 1536MB |
Cluster: | Cube (Intel G860) |
Languages: | All except: ASM64 |
hide comments
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2018-08-12 13:55:38
Easy Peasy.Just remember formula for exponential increment of insects - N = No * e^rate*time |
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2016-08-10 08:38:37 sharif ullah
Just use physics formula N=No e^-lemda*t |
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2016-06-21 18:42:46
WA in c++ .... AC in c!! |
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2016-02-05 14:07:04
A typical "Project Manager" problem ;) 9 women will not produce 1 child in 1 month :) If it takes 3 seconds for amoeba to split, even after 2,99 seconds you'll have still only 10 amoebas in your room. And in 3,01 second you'll suddenly have 20 of them. |
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2015-09-01 20:19:05 pranay
use first order equilibrium rate equation |
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2015-08-23 10:11:11 shravinson
got 1 WA because of output pattern... my 1st century Last edit: 2015-08-23 10:11:40 |
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2015-07-28 14:12:13
solution of the problem is depends completely on this line their growth rate is proportional to the number of creatures at a certain time. |
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2015-07-12 23:05:18 scyth3r
INPUT: 4 10 15 3 15 10 15 3 20 5 12 2 50 5 12 2 7 OUTPUT: Scenario #1: 3.00 Scenario #2: 5.13 Scenario #3: 5.26 Scenario #4: 0.77 There exists no blank line in input and output. Got 2 NZEC bcoz of that |
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2015-06-03 21:05:01 viju11
there is a space b/w Scenario & # and b/w ":" and answer. costed me many wrong answers -_- |
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2015-05-26 21:39:06 Rishabh Joshi
Keep getting NZEC in C#. AC in C. -_- Last edit: 2015-05-26 21:46:10 |