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TEST - Life, the Universe, and Everything |
Your program is to use the brute-force approach in order to find the Answer to Life, the Universe, and Everything. More precisely... rewrite small numbers from input to output. Stop processing input after reading in the number 42. All numbers at input are integers of one or two digits.
Example
Input: 1 2 88 42 99 Output: 1 2 88
Information
In case of any problems with your code, you can take a look in the forum, you'll find the answer, only for this problem, in various languages.
| Added by: | mima |
| Date: | 2004-05-01 |
| Time limit: | 4s |
| Source limit: | 50000B |
| Memory limit: | 1536MB |
| Cluster: | Cube (Intel G860) |
| Languages: | All |
| Resource: | Douglas Adams, The Hitchhiker's Guide to the Galaxy |
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2015-01-20 03:21:05 Prahalad
To all those who struggled to get this thing working like .. your aim is to write a program whch display EXACT Input and output minus the cout<<"Enter a no",also dont forget to add excpetion atleast io etc .. |
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2015-01-20 03:21:05 David Harkness
@V N V Vinod - The first line is not the count of numbers to be read. Read and print every number until you read 42, then stop. |
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2015-01-20 03:21:05 Gaurav Juneja
my program isworking fine but it shows compilation error |
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2015-01-20 03:21:05 Anubhav Saini
@Mohit Relwani There is no conio.h in 'C' language. Stop using Borland/Turbo C++ compiler. Install linux 'cc' : C compiler. |
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2015-01-20 03:21:05 Klinik Tong Fang
@saba : Actually, the compiler in SPOJ read the input from their nefile and write it to other file. So it's fine to simultaneously printf/cout them soon after you scanf/cin. It's only took 11 row to make this, more or less |
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2015-01-20 03:21:05 mihir
how do i terminate\ |
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2015-01-20 03:21:05 saba
do we have to accept all nos first and then display them in the output or simultaneously display them?? |
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